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zvonat [6]
3 years ago
8

Write an explicit formula for an, the nth term of the sequence 40, 35, 30, ....

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
8 0

Answer:

Tn= 5(n)+ oth term

Step-by-step explanation:

Its the formula

Vladimir79 [104]3 years ago
5 0

Answer: an=40-5(n-1)

Step-by-step explanation:

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Answer: 42 yards :)

Step-by-step explanation:

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na2s + hcl _____ nacl + h2s Which of these would represent the coefficients needed to balance this equation? A) 1, 1, 1, 1 B) 1,
USPshnik [31]

Answer:

B) 1, 2, 2, 1

Step-by-step explanation:

In given equation:

Left side:                                Right Side:

  2 Na                                          1 Na

  1 S                                              1 S

  1 H                                             2 H

  1 Cl                                             1 Cl

To equal the number of Na and H atoms on both sides, HCl and NaCl will have a coefficient of 2 to balance the equation while Na₂S and H₂S will have a coefficient of 1.

1 Na₂S + 2 HCl ⇒ 2 NaCl + 1 H₂S

5 0
3 years ago
An 18% discount on a watch saved a shopper $72. Find the price of the watch before the discount
Mamont248 [21]
1% = $4

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3 years ago
√3=1.732 find the value of√75+1/2√48-√198​
Nookie1986 [14]

Answer:

12.124-3\sqrt{22}

Step-by-step explanation:

\sqrt{75} = \sqrt{5^{2}*3} \\

\sqrt{48}= \sqrt{2^{2}*2^{2}*3} \\

\sqrt{198} =\sqrt{3^{2}*2*11} \\

\sqrt{75} +\frac{1}{2} *\sqrt{48} - \sqrt{198} \\\\\sqrt{5^{2}*3} +\frac{1}{2} *\sqrt{2^{2}*2^{2}*3} - \sqrt{3^{2}*2*11} \\\\5\sqrt{3} +\frac{1}{2} *4 \sqrt{3} - 3 \sqrt{2*11} \\\\5\sqrt{3} +2 \sqrt{3} - 3 \sqrt{22} \\\\5*1.732 +2*1.732 - 3 \sqrt{22} \\\\8.66 + 3.464 - 3 \sqrt{22}\\\\12.124- 3 \sqrt{22}

4 0
3 years ago
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