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ololo11 [35]
3 years ago
14

Two pendula are shown in the figure. Each consists of a solid ball with uniform density and has a mass M. They are each suspende

d from the ceiling with massless rod as shown in the figure. The ball on the left pendulum is very small. The ball of the right pendulum has radius 1/2 L.
Find the period T of the right pendulum for small displacements in s.
Physics
1 answer:
steposvetlana [31]3 years ago
6 0

The period (T) of the right pendulum for small displacements in s is equal to 1.49 seconds.

<h3>How to calculate the period (T).</h3>

Mathematically, the time taken by this pendulum to undergo a small displacement is given by this formula:

T=2\pi \sqrt{\frac{L}{g} }

<u>Where:</u>

  • L is the length.
  • g is the acceleration due to gravity.

Scientific data:

Acceleration due to gravity (g) = 9.8 m/s².

Assuming a randomized variable for the length of the rope to be 1.2 meter. Also, we know that the right pendulum has a radius of 1/2L.

1/2L = L/2

L/2 = 1.1/2

L/2 = 0.55 meter.

Substituting the parameters into the formula, we have;

T=2\times 3.142 \sqrt{\frac{0.55}{9.8} }\\\\T=6.284 \times \sqrt{0.0561} \\\\T=6.284 \times 0.2369

T = 1.49 seconds.

Read more on a pendulum here: brainly.com/question/20070798

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