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2 years ago

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An ideal gas occupies a volume of 0.60 m3 at 5.0 atm and 400. K. What volume does it occupy at 4.0 atm and a temperature of 200.

K?

1 answer:

kotegsom [21]2 years ago

7 0

V1 = 0.60 m3, P1 = 5.00atm, T1=400K
V2 = ??m3, P2 = 4.00atm, T2=200K
P1V1/T1 = P2V2/T2
V2 = T2P1V1/T1P2 = 200×5×0.60/400×4.00 = 600/1600
V2 = 0.38 m3

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Read 2 more answers

Two forces, one of 100 ponds and the other 150 pounds act on the same object, at angles of 20°and 60°, respectively, withthe pos

soldi70 [24.7K]

<h2>Resultant is 235.54 pounds at an angle 44.16° to X axis.</h2>

Explanation:

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That is force 1 is 100 pound with x axis at 20°

F₁ = 100 cos 20 i + 100 sin 20 j

F₁ = 93.97 i + 34.20 j

That is force 2 is 150 pound with x axis at 60°

F₂ = 150 cos 60 i + 150 sin 60 j

F₂ = 75 i + 129.90 j

F₁ + F₂ = 93.97 i + 34.20 j + 75 i + 129.90 j

F₁ + F₂ = 168.97 i + 164.10 j

$\texttt{Magnitude = }\sqrt{168.97^2+164.10^2}\\\\\texttt{Magnitude = }235.54pounds\\\\\texttt{Angle = }tan^{-1}\left ( \frac{164.10}{168.97}\right )\\\\\texttt{Angle = }44.16^0$

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2 years ago

A backyard swimming pool with a circular base of diameter 6.00m is filled to depth 1.50m. (b) Two persons with combined mass 150

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The pressure increase at the bottom of the pool after they enter the pool and float is 106.103 Pa.

<h3>What is absolute pressure?</h3>

Absolute pressure is the force that exists in a space when there is no matter present, or when there is a perfect vacuum. This absolute zero serves as the baseline for measurements in absolute pressure. The measurement of barometric pressure is the greatest illustration of an absolute referenced pressure. In order to determine absolute pressure, a complete vacuum is used. In contrast, gauge pressure is the amount of pressure that is measured in relation to atmospheric pressure, also referred to as barometric pressure.

given,

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a) absolute pressure

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P = 1.15 x 10⁵ Pa

b) When two person enters into the pool,

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weight of water level displaced exists equal to the weight of person.

$\rho \mathrm{Vg}=2 \mathrm{mg} \\$

$V=\frac{2 m}{\rho} \\$

$V=\frac{2 \times 150}{1000} \\$

$\mathrm{~V}=0.3 \mathrm{~m}^3$

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$&=\frac{\pi}{4} \times 6^2 \\$

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$h &=\frac{V}{A} \\$

$h &=\frac{0.3}{28.27} \\$

$& \mathrm{~h}=0.0106 \mathrm{~m}$

Pressure increased

P = ρ g h

P = 1000 x 10 x 0.0106

P = 106.103 Pa

To learn more about absolute pressure refer to:

brainly.com/question/17200230

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