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Anit [1.1K]
2 years ago
13

Options are a) -2 and 12/5 b) 1 and 2 c)8/3 and 2 d) 3 and 4

Mathematics
1 answer:
tigry1 [53]2 years ago
6 0
A) 1 and 2
That is the correct answer
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Michelle, Jennifer, and Betty volunteered to make cupcakes for a school fundraiser. They've been asked to make 100 cupcakes. Mic
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3 years ago
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For which pair of triangles would you use AAS to prove the congruence of the 2 triangles
DerKrebs [107]

Answer:

The correct option is B.

Step-by-step explanation:

According to AAS congruence rule, two triangles are congruent if two angles and a non included side are congruent to corresponding angles and side of another triangle.

We need two angles and a non included side, to use AAS postulate.

In option A, two sides and their inclined angle are congruent, therefore these triangles are congruent by SAS postulate and option A is incorrect.

In option B, two angles and a non included side are congruent, therefore these triangles are congruent by AAS postulate and option B is correct.

In option C, two angles and their included side are congruent, therefore these triangles are congruent by ASA postulate and option C is incorrect.

In option D, all sides are congruent, therefore these triangles are congruent by SSS postulate and option D is incorrect.

8 0
3 years ago
Read 2 more answers
1) What is the solution of the given system?
m_a_m_a [10]

Answer:

1  x=-2.5  y = -5.5

2.  x=5  y=1

Step-by-step explanation:

1) What is the solution of the given system?

5x-y=-7

3x-y=-2

Multiply the second equation by -1

-1*(3x-y)=-1(-2)

-3x +y = 2


Now add the first equation to the modified second equation

5x-y=-7

-3x +y = 2

------------------

2x = -5

Divide each side by 2

2x/2 = -5/2

x = -2.5

Now we need to find y

-3x+y =2

-3(-2.5) +y =2

7.5 +y =2

Subtract 7.5 from each side

7.5 -7.5 +y =2-7.5

y = -5.5


2) what is the solution of the given system?

5x+7y=32

8x+6y=46

Divide the second equation by 2

8x/2+6y/2=46/2

4x+3y =23


Multiply the first equation by 4

4 (5x+7y)=32*4

20x+28y = 128


Now multiply the modified 2nd equation by -5

-5(4x+3y )=-5(23 )

-20x -15y = -115


Lets add the new equations together to eliminate x

20x+28y = 128

-20x -15y = -115

---------------------

      13y = 13

Divide each side by 13

13y/13 =13/13

y=1

Now substitute back in to find x

5x+7y=32

5x +7(1) =32

5x +7 =32

Subtract 7 from each side

5x+7-7 =32-7

5x =25

Divide by 5

5x/5 =25/5

x=5





3 0
3 years ago
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