Answer:
12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).
Explanation:
<span>The stage at which all the cells show crossover chromosomes is meiotic prophase I. The crossover is the exchange of genetic material between homologous chromosomes. Homologous chromosomes are present in the meiosis I. Regarding the phase of meiosis I, it is expected that the crossover takes place in meiotic prophase I since homologous chromosomes pair up in the prophase.</span>
Answer:
D. heterotrophic by ingestion, pseudopods
Explanation:
Protists are generally classified as all eukaryotic organisms that are not plants, animals or fungi. Example is amoeba, paramecium etc.They may be unicellular or multi cellular in nature.Most exist in colonies.
Their mode of nutrition can be photosynthetic or hetrotrophic. Hetrotrophic protists can be divided into phagotrophs and osmotrops/saprotrophs. The phagotrophs makes use of the cell body to engulf the food materials as in amoeba ,carry out extracellular digestion before swallowing it.
Osmotrops absorbed dissolved food from surrounding liquid environments directly. (Some photosynthetic protists can also be heterotrophic.
Amoeboid movement is the mode of locomotion of protists and some other eukaryotes. It involved the protrusion of cytoplasm, which exert pressure on the cell membrane to form pseudopodia and the posterioly evolved <u>Uropods. </u>
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<u>Sol-gel theory has been proposed to expalin this movements, The ectopalsm of amoeba is gelly-like , while the endiplams is less viscpus and said to be sol. The interchange of the cytoplasmic fluis between the endo-and ecto plasm gives the SOL-GEL propulsion of the protopalms for the amoebic moveemnts .</u>
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<u>The false feet(psuedopodium) drags the amoeba along in the direction of the flow of the cytoplasm.</u>
Therefore option D is the right option
