Answer: <em>(gºh)(25)=2</em>
Step-by-step explanation:
1. This exercise is about Composition of functions, then you have:
2. Then, you have that
<em>(gºh)(25)</em>
3. Now, you must substitute 25 into the function, as you can see below:
<em>(gºh)(25)</em>
4. Simplify the fucntion.
5. Therfore, you obtain:
<em>(gºh)(25)</em>
![\left[\begin{array}{ccc}-1&2&1\\1&-4&1\\-2&-2&1\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%262%261%5C%5C1%26-4%261%5C%5C-2%26-2%261%5Cend%7Barray%7D%5Cright%5D%20%20)
Find the determinant
D = [(-1).(-4).1 + 2.1.(-2) + 1.1.(-2)] - [1.(-4).(-2) + (-1).1.(-2) + 2.1.1]
D = [4 - 4 - 2] - [8 + 2 + 2]
D = -10 - 12
D = -22
A = |D|/2
A = |-22|/2
A = 22/2
A = 11
Answer:
x
<
−
3
Step-by-step explanation:
Given:


To find:
Whether the above functions are proportional or non-proportional?
Solution:
If y is proportional to x, then


where, k is constant of proportionality.
The proportional relationships are in the form of
and they passes through (0,0).
Putting x=0 and y=0 in the given equations.



It is a true statement.




It is a false statement.
Therefore,
is proportional and
is non-proportional.