1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sladkaya [172]
3 years ago
5

A while loop is frequently used to ______________ data.

Computers and Technology
1 answer:
zaharov [31]3 years ago
5 0
I believe the answer to your question is A but i’m not 100% sure
You might be interested in
Why are there problems with patching electronics such as heart rate monitors and MRI machines that run embedded Windows OSs?
timofeeve [1]

Answer:

The various problems with patching electronics such as heart rate monitors and MRI machines that run embedded Windows OSs is that they have a certification which is usually at a specific revision level.

Another issue is that probably the maker or the manufacturer didn’t provide the patch method which would have been used to fix such electronics.

8 0
3 years ago
Write some positive and negative impacts of computer in our daily life​
8090 [49]
Positive impacts are
1. Communicating with people
2. Daily update of what going on in the world
3. learn new things
Negative impacts are
1. Viruses
2. Private information shared
3. Less face to face conversations
3 0
3 years ago
Which of the following functions grows at a faster rate than the rest? (Points : 6)
ehidna [41]

Answer:

n2.

Explanation:

The function with the time complexity of n2 is the fastest growing function is in terms of square.As n increases the time complexity will grow very rapidly.

n=1   n2=1

n=2   n2=4

n=3   n2=9

n=4   n2=16

n=5   n2=25.

The slowest growing function among them is log n then n and then n log n.

n log n is better than n2.

4 0
3 years ago
Open and close ____ immediately following the name of a procedure identify a Visual Basic statement as a procedure call statemen
Bezzdna [24]

Answer:  Parentheses

Explanation:

 The open and close parentheses basically identify the visual basic statement   in the procedure call statement.

The close procedure basically in the visual basic statement basically terminate the call of a program that performed the real processing. Open and close is also known as right and left parentheses.

The close statement is basically control the pre-defined programming statement in the particular close procedure.

 

4 0
4 years ago
Given two complex numbers, find the sum of the complex numbers using operator overloading.Write an operator overloading function
Inessa05 [86]

Answer:

I am writing the program in C++ programming language.  

#include<iostream>  // to use input output functions

using namespace std;   // to identify objects like cin cout

class ProblemSolution {  //class name

private:  

// private data members that only be accessed within ProblemSolution class

int real, imag;

 // private variables for real and imaginary part of complex numbers

public:  

// constructor ProblemSolution() to initialize values of real and imaginary numbers to 0. r is for real part and i for imaginary part of complex number

ProblemSolution(int r = 0, int i =0) {  

real = r; imag = i; }  

/* print() method that displays real and imaginary part in output of the sum of complex numbers */

void print(){  

//prints real and imaginary part of complex number with a space between //them

cout<<real<<" "<<imag;}  

// computes the sum of complex numbers using operator overloading

ProblemSolution operator + (ProblemSolution const &P){  //pass by ref

          ProblemSolution sum;  // object of ProblemSolution

          sum.real = real + P.real;  // adds the real part of the  complex nos.

          sum.imag = imag + P.imag;  //adds imaginary parts of  complex nos.

//returns the resulting object

          return sum;       }  //returns the sum of complex numbers

};   //end of the class ProblemSolution

int main(){    //start of the main() function body

int real,imag;  //declare variables for real and imaginary part of complex nos

//reads values of real and imaginary part of first input complex no.1

cin>>real>>imag;  

//creates object problemSolution1 for first complex number

ProblemSolution problemSolution1(real, imag);  //creates object

//reads values of real and imaginary part of first input complex no.2

cin>>real>>imag;

//creates object problemSolution2 for second complex number

ProblemSolution problemSolution2(real,imag);

//creates object problemSolution2 to store the addition of two complex nos.

ProblemSolution problemSolution3 = problemSolution1 + problemSolution2;

problemSolution3.print();} //calls print() method to display the result of the //sum with real and imaginary part of the sum displayed with a space

Explanation:

The program is well explained in the comments mentioned with each statement of the program. The program has a class named ProblemSolution which has two data members real and imag to hold the values for the real and imaginary parts of the complex number. A default constructor ProblemSolution() which initializes an the objects for complex numbers 1 and 2 automatically when they are created.

ProblemSolution operator + (ProblemSolution const &P) is the operator overloading function. This performs the overloading of a binary operator + operating on two operands. This is used here to add two complex numbers.  In order to use a binary operator one of the operands should be passed as argument to the operator function. Here one argument const &P is passed. This is call by reference. Object sum is created to add the two complex numbers with real and imaginary parts and then the resulting object which is the sum of these two complex numbers is returned.  

In the main() method, three objects of type ProblemSolution are created and user is prompted to enter real and imaginary parts for two complex numbers. These are stored in objects problemSolution1 and problemSolution2.  Then statement ProblemSolution problemSolution3 = problemSolution1 + problemSolution2;  creates another object problemSolution3 to hold the result of the addition. When this statement is executed it invokes the operator function ProblemSolution operator + (ProblemSolution const &P). This function returns the resultant complex number (object) to main() function and print() function is called which is used to display the output of the addition.

4 0
4 years ago
Other questions:
  • Write the definition of the word "log" as it would be used in relation to digital literacy
    13·1 answer
  • Sarah's employer purchased a health insurance plan that costs $750 per month. Sarah pays $75 toward the plan each month. What is
    5·2 answers
  • (The Location class) Design a class named Location for locating a maximal value and its location in a two-dimensional array. The
    10·1 answer
  • What is the Documenter?
    10·1 answer
  • Suppose Host A sends two TCP segments back to back to Host B over a TCP connection. The first segment has sequence number 90; th
    8·2 answers
  • Can you give me a long list of anime
    6·2 answers
  • Security administrator for your organization utilized a heuristic system to detect an anomaly in a desktop computer's baseline.
    7·1 answer
  • Multiple Choice: We have been assigned the task of developing a software testing tool (tester) that can assess reachability of s
    11·1 answer
  • Write the thesis statment of research paper​
    5·1 answer
  • Microsoft Office PowerPoint 2016 enables you to create robust multimedia _______.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!