Answer:
h = 6
Step-by-step explanation:
Given he area of the banner expressed as;
A = ℎ(2ℎ−2)
h is the height of the banner
A is the area = 60
Substitute
60 = ℎ(2ℎ−2)
60 = 2h² - 2h
30 = h² - h
h²-h-30 = 0
Factorize;
h²-6h+5h-30 = 0
h(h-6)+5(h-6) = 0
(h-6)(h+5) = 0
h - 6 = 0 and h+5 = 0
h = 6 and -5
Since the height cannot be negative;
h = 6
Hence he height of the banner is 6
A NONA=9, nonagon has 9 sides, so it's perimeter is 7+7+7+7+7+7+7+7+7, or 63, and we know the apothem.
bearing in mind that the area of a regular polygon is
(1/2)ap a = apothem, p = perimeter
so in this case that'd be (1/2)(5)(63).
Answer:
above is the solution to the question
Both the work and explanation is in the picture.