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Goryan [66]
3 years ago
11

In the figure,BC andAD are line segments. What is the sum of x and y?

Mathematics
1 answer:
Alika [10]3 years ago
7 0
Can you please post the image.
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Consider the equation, where p is a real number coefficient.
vazorg [7]
This should help here you go

5 0
3 years ago
The fifth grade class donation consisted of 1/5 pasta boxes and 6/15 cans of soup. What fraction of their total donation was veg
vesna_86 [32]

Answer:

None?

Step-by-step explanation:

3 0
3 years ago
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3. A fast food joint sells 5 boxes of chicken nuggets for $33.90. Another fast food joint sells 4 boxe:
mrs_skeptik [129]
33.90/5= 6.78 or 26.88/4= 6.72. The 4 boxes of chicken fingers has the cheaper unit price
3 0
3 years ago
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
3.92 rounded to the nearest tenth​
Troyanec [42]
3.92 rounded to the nearest tenth should be 4.00 or 4, sorry if I’m wrong, have a good rest of your day/night
5 0
3 years ago
Read 2 more answers
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