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2 years ago

Factor the following equation below: 2m^2+2m-12=0

Mathematics

2 answers:

givi [52]2 years ago

6 0

M= 3 is the correct answer

m_a_m_a [10]2 years ago

5 0

M=2 or m=-3 hope this helps

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A model rocket is launched with an initial velocity of 200 ft per second. The height h, in feet, of the rocket t seconds after t

Solnce55 [7]

Answer:

2.10 s, 10.40 s.

Step-by-step explanation:

We know that the height of the rocket is given by the function:

$h=-16t^2+200t$

We are asked to find the time for which the height of the rocket will be 350 ft. So, for that moment, we know the height but we don't know the time; however, we know that the equation can help us to find the time, doing h=350:

$350=-16t^2+200t$

The last is a quadratic equation, which can be put in the form $at^2+bt+c=0$ and solved applying the formula:

$t=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

So, let's put the equation on the form $at^2+bt+c=0$ adding $16t^2$ and subtracting $200t$ to each side of the equation; the result is:

$16t^2-200t+350=0$

So, we note that a=16, b=-200, and c=350.

Then,

$t_1=\frac{200-\sqrt{200^2-4*16*350} }{2*16}=2.10$

$t_2=\frac{200+\sqrt{200^2-4*16*350} }{2*16}=10.40$

According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.

4 0

2 years ago

J'ai un exercice de maths pour demain merci de commenter au plus vite

kari74 [83]

Oui je peux the aider

8 0

2 years ago

Can anyone answer these 4? if so ill give 40 points. please show work!! and no long division please. , thanks!

dolphi86 [110]

54x89=4806

123x85=10,455

64x15=960

264x14=3,696

6 0

2 years ago

the bowling alley charges a flat rate of $50 for a birthday party plus $4.25 per person. If Emanuel only has $125 to spend. How

Maksim231197 [3]

125 > 50 + 4.25*p

subtract 50 from each side

75 =>4.25p

divide by 4.25

p>17.64

He may invite up to 17 people ( if he doesn't have to pay for himself)

He may invite 16 if he has to pay for himself

3 0

2 years ago

You are making identical gift bags using 12 crayons and 28 bottles of bubbles. What is the greatest number of gift bags you can

const2013 [10]

Since you don't want any leftover items, you have to find the greatest common factor (GCF) of both the crayons and bubbles. Since the highest common factor for both 28 and 12 is 4, the greatest number of gift bags you can make without any leftover items would be 4 gift bags.

Hope I could help.

4 0

2 years ago