Question

I provided the answers I just need you to show work. I’ll even mark you the Brainliest!

Answer 1

The intercepts and the graph on your worksheet are not correct. Please see below for details:

$x^2-2x-3=0$ has solutions at x=-1 and x=3 (use the quadratic formula to solve). That means these are the x-intercepts, namely points:

(-1,0) and (3,0).

The y-intercept comes from setting x=0 and calculating the y value:

$y=0^2-2\cdot0-3=-3$

so the y-intercept is (0,-3).

Now to the graph: Based on the form of the function we can see this is a quadratic function and its graph will be a parabola. You can reformat the expression in the following form

$y = x^2-2x-3=(x-1)^2-4$

and that will indicate that the apex of the parabola (open up) will be at the point (1,-4).

Knowing the apex, the x intercepts, and the y intercept, we can graph it now.

Graph is in the image attached.