Answer:
There were 10 flies originally
Step-by-step explanation:
Since we have an exponential growth, we will be having a constant percentage of increase and we can set up the increase at any day using the following equation;
V = I(1+r)^d
where V is the number of flies on a particular day
I is the initial number of flies
r is the constant increase in percentage
and d is the number of days.
So we have for the second day;
60 = I(1+r)^2 ••••••(i)
For the fourth day, we have;
360 = I(1+r)^4 ••••••••(ii)
divide equation ii by i; we have;
360/60 = (1+r)^4/(1+r)^2
6 = (1+r)^2
(√6)^2 = (1+r)^2
1 + r = √6
r = √6 - 1
So we can substitute the value of r in any of the equations to get I which is the initial number of flies
Let’s use equation 1
60 = I(1 + r)^2
60 = I(1 + √6 -1)^2
60 = I(√6)^2
60 = 6I
I = 60/6
I = 10 flies
Answer:
-2
Step-by-step explanation:
You make x= -3 then you insert it into the problem which is x= 2(-3)+4
2 times -3 is -6 which then you would get
-6+4 which equals -2
Answer:
B -⅓
Step-by-step explanation:
sinx = -3/5
Adjacent² = 5² - 3² = 16
Adjacent = 4
tan(x) = -3/4
-¾ = 2tan(½x)/[1 - tan²(½x)]
-3 + 3tan²(½x) = 8tan(½x)
3tan²(½x) - 8tan(½x) - 3 = 0
tan(½x) = 3, -⅓
I Think The answer is c I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
Answer:
A
Step-by-step explanation:
