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enot [183]
2 years ago
13

How many moles are needed to make 2.5 L of a 3.8 M solution?

Chemistry
1 answer:
erik [133]2 years ago
4 0

Answer:

9.5

Explanation:

that the answer I hope am correct

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Select the most likely product for this reaction:
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Answer:

A

Explanation:

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3 years ago
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Below are shown, for five metals, reduction reactions and standard electrode potential values. which of these metals is the leas
just olya [345]
Above question is incomplete. Complete question is attached below
........................................................................................................................
Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.

In present case, reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is least reactive.

On other hand, reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is most reactive. 


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4 years ago
A ground-state H atom absorbs a photon of wavelength 94.91 nm, and its electron attains a higher energy level. The atom then emi
vitfil [10]

The intermediate energy level that the electron reached from the ground state is; n= 3.

<h3>What are energy levels in an atom?</h3>

The fixed distances from an atom's nucleus where electrons may be found are referred to as energy levels (also known as electron shells). Higher energy electrons have greater energy as you move out from the nucleus.

A region of space within an energy level known as an orbital is where an electron is most likely to be found.

The formula to get the higher level is Rydberg's formula;

1/λ = R(1/n₁² - 1/n₂²)

where;

R is rydberg constant = 1.097 × 10⁷ m⁻¹

We want to find the intermediate level where wavelength = 1281 nm = 1281 × 10⁻⁹ m

Thus;

\frac{1}{1280(10^{-9})} = 1.097*10^{7}(\frac{1}{n_{2}^{2}}-\frac{1}{5^{2}})  \\0.0712=\frac{1}{n_{2}^{2}}-\frac{1}{25}  \\\frac{1}{n_{2}^{2}}=0.0712+\frac{1}{25}\\\frac{1}{n_{2}^{2}}=0.1112

n₂ = √(1/0.1112)

n₂ ≈ 3

To know more about energy levels, visit: brainly.com/question/10763798

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