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Travka [436]
3 years ago
10

Draw all possible structures for a compound with molecular formula C4H8O that exhibits a broad signal between 3200 and 3600 cm-1

in its IR spectrum and does not contain any signals between 1600 and 1850 cm-1.

Chemistry
1 answer:
MrRissso [65]3 years ago
4 0

Answer:

Cyclic butanol , 1 cyclopropyl methanol, 1-methyl cyclo propan-1-ol.

Explanation:

IR wave-number of O-H bond = 3600 - 3200 cm^{-1}

The intensity of the signal is broad and strong.

IR wave number of C=C bond = 1680 - 1600 cm^{-1}

The intensity of the signal is weak.But for the given chemical formula it didn't show any signal in its IR spectrum.This means that no unsaturation is present.

IR wave number of C=O bond = 1780 - 1650 cm^{-1}

The intensity of the signal is broad and strong.But for the given chemical formula it didn't show any signal in its IR spectrum. This means that no C=O is present in the compound

For the given formula the possible structures wil be:

C_4H_8O: C_4H_7OH

As we know from the I.R. data that no unsaturation is present which indicates that the given compound has cyclic structure.

The possible structures are attached in an image.

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He fuel used in many disposable lighters is liquid butane, c4h10c4h10. butane has a molecular weight of 58. 1 grams in one mole.
snow_lady [41]

Carbon atoms present in 2. 00 g of butane is 8.28 × 10^22.

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Multiply the number of moles by Avogadro's number. This will let you obtain the number of butane molecules:

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Now multiply this number by four (due to four carbon atoms per butane molecule) to obtain the answer:

so, no. of carbon atoms = 4 x 2.07x 10^22 = 8.28x 10^22 atoms.

Thus the no. of carbon atom is 8.28×10^22.

learn more about butane or moles:

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