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Travka [436]
2 years ago
10

Draw all possible structures for a compound with molecular formula C4H8O that exhibits a broad signal between 3200 and 3600 cm-1

in its IR spectrum and does not contain any signals between 1600 and 1850 cm-1.

Chemistry
1 answer:
MrRissso [65]2 years ago
4 0

Answer:

Cyclic butanol , 1 cyclopropyl methanol, 1-methyl cyclo propan-1-ol.

Explanation:

IR wave-number of O-H bond = 3600 - 3200 cm^{-1}

The intensity of the signal is broad and strong.

IR wave number of C=C bond = 1680 - 1600 cm^{-1}

The intensity of the signal is weak.But for the given chemical formula it didn't show any signal in its IR spectrum.This means that no unsaturation is present.

IR wave number of C=O bond = 1780 - 1650 cm^{-1}

The intensity of the signal is broad and strong.But for the given chemical formula it didn't show any signal in its IR spectrum. This means that no C=O is present in the compound

For the given formula the possible structures wil be:

C_4H_8O: C_4H_7OH

As we know from the I.R. data that no unsaturation is present which indicates that the given compound has cyclic structure.

The possible structures are attached in an image.

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jeka57 [31]

Answer:

2 mole of Sodium hydroxide reacts with 1 mole of Sulfuric acid

Explanation:

Write down the equation in the beginning with reactants and products:

NaOH + H₂SO₄ → Na₂SO₄ + H₂0

Now try to balance it. Try with Na first:

2NaOH + H₂SO₄ → Na₂SO₄ + H₂0

Na atoms are balanced. There are 6 Oxygen atoms on the right and 5 on the left. Balance by increasing the H₂O moles:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂0

Check if H atoms are also balanced. They are. That means our final reaction is:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂0

2 Moles of NaOH reacts with 1 mole of H₂SO₄

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Chemistry: counting atoms in compounds worksheet #7.0.1<br> Answer please!!!!!
stealth61 [152]
Counting atoms in a compound can be done by taking one element at a time and multiplying the subscript of the element and the number of molecules of the compounds. For example, H2O, there are two atoms of H adn 1 atom of oxygen. 
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If the ph of hc3h5o2 is 4.2 and the ka 1.34x10^-5, what is the equilibrium concentration
n200080 [17]
<span>CH</span>₃<span>CH</span>₂<span>COOH + H</span>₂<span>O </span>↔ <span> CH</span>₃<span>CH</span>₂<span>COO</span>⁻<span> + H</span>₃<span>O</span>⁺<span> 
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pH = 0.5 pKa + 0.5 pCa
0.5 pCa = pH - 0.5 pKa
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