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Travka [436]
3 years ago
10

Draw all possible structures for a compound with molecular formula C4H8O that exhibits a broad signal between 3200 and 3600 cm-1

in its IR spectrum and does not contain any signals between 1600 and 1850 cm-1.

Chemistry
1 answer:
MrRissso [65]3 years ago
4 0

Answer:

Cyclic butanol , 1 cyclopropyl methanol, 1-methyl cyclo propan-1-ol.

Explanation:

IR wave-number of O-H bond = 3600 - 3200 cm^{-1}

The intensity of the signal is broad and strong.

IR wave number of C=C bond = 1680 - 1600 cm^{-1}

The intensity of the signal is weak.But for the given chemical formula it didn't show any signal in its IR spectrum.This means that no unsaturation is present.

IR wave number of C=O bond = 1780 - 1650 cm^{-1}

The intensity of the signal is broad and strong.But for the given chemical formula it didn't show any signal in its IR spectrum. This means that no C=O is present in the compound

For the given formula the possible structures wil be:

C_4H_8O: C_4H_7OH

As we know from the I.R. data that no unsaturation is present which indicates that the given compound has cyclic structure.

The possible structures are attached in an image.

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Vera_Pavlovna [14]
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I think if you added a proton you would have chlorine.


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6 0
3 years ago
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How many grams of nitrogen dioxide are required to produce 5.89x10^3 kg of hno3 in excess water
polet [3.4K]
<span>3 NO2 + H2O -------->. 2 HNO3. + NO
3(46g)------------------------> 2 ( 63g) HNO3
? kg-------------------------5.89 x10^3kg HNO3
Mass of NO2. = 5.89x10^3 x 138/ 2(63) = 6.45 x10^3 kg</span>
5 0
3 years ago
If 1.02 g of nickel reacted with 750. mL of 0.112 M hydrobromic acid, how much of each will be present at the end of the reactio
kati45 [8]

Answer:

35.1% is percent yield

Explanation:

<em>Full question: Assume no volume change.  If you formed 0.0910 atm of gas, what is the percent yield?</em>

<em />

The reaction that is occurring is:

Ni + 3HBr → NiBr₃ + 3/2H₂(g)

First, we will determine moles of Ni and HBr to determine limiting reactant and theoretical yield

Using ideal gas law, we can determine the moles of hydrogen formed. Thus, we can find percent yield:

<em>Moles Ni (Molar mass: 58.69g/mol):</em>

1.02g * (1mol / 58.69g) = 0.01738moles Ni

<em>Moles HBr:</em>

0.750L * (0.112mol/L) = 0.084 moles of HBr.

For a complete reaction of the 0.084 moles of HBr you need:

0.084mol HBr * (1 mole Ni / 3 moles HBr) = 0.028 moles of Ni.

As there are just 0.01738 moles of Ni, the Ni is limiting reactant. Assuming a theoretical yield, moles of H₂ produced are:

0.01738moles Ni * (3/2 H₂ / 1 mol Ni) = 0.02607 moles H₂

Now, moles of H₂ produced are:

PV = nRT

PV/RT = n

<em>Where P is pressure (0.0910atm)</em>

<em>V is volume (2.50L)</em>

<em>R is gas constant (0.082atmL/molK)</em>

<em>T is absolute temperature in Kelvin (30°C + 273.15 = 303.15K)</em>

<em>And n are moles</em>

PV/RT = n

0.0910atm*2.50L/0.082atmL/molK*303.15K = n

0.00915 moles = n

<em />

And percent yield (Produced moles / Theoretical moles * 100) is:

0.00915 moles / 0.02607moles =

<h3>35.1% is percent yield</h3>
8 0
3 years ago
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lawyer [7]

Answer:I think it’s A.Positive. Not sure though.

Explanation:

7 0
3 years ago
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Silver nitrate solution reacts with calcium chloride solution according to the equation: 2 AgNO3 + CaCl2 → Ca(NO3)2 + 2 AgCl All
HACTEHA [7]

Answer:

14.33 g

Explanation:

Solve this problem based on the stoichiometry of the reaction.

To do that we need the molecular weight of the masses involved and then calculate the number of moles, find the limiting reagent and  finally calculate the mass of AgCl.

                      2 AgNO₃   + CaCl₂    ⇒   Ca(NO₃)₂   + 2 AgCl

mass, g                  6.97        6.39                                     ?

MW ,g/mol         169.87      110.98                                  143.32

mol =m/MW           0.10         0.06                                    0.10

From the table above AgNO₃ is the limiting reagent and we will produce 0.10 mol AgCl which is a mass :

0.10 mol x 143.32 g/mol = 14.33 g

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3 years ago
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