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Firdavs [7]
2 years ago
8

A car can accelerate from a standstill to 100 km/h [E] in 9.60s. calculate the average acceleration

Chemistry
1 answer:
Lelu [443]2 years ago
5 0

Answer:

Acceleration is :

a = 2.89 m/s2

Explanation:

Acceleration : It is the change in the velocity of the object per unit time.

The object starts from the rest , so the initial velocity of the object is zero.

Initial velocity , u = 0

Final velocity = 100 km/h

Change the velocity to m/s because[ time unit is in second(9.60 s)]

1 km = 1000 m

1 hour = 60 x 60 sec = 3600 sec

1km/h=\frac{1000}{3600}m/s

1km/hr=\frac{5}{18}

100km/hr=\frac{5}{18}\times 100

v=\frac{5}{18}\times 100

v = 27.78 m/s

u = 0 m/s

time = 9.60 s

The acceleration"a" is calculated using :

a=\frac{v-u}{t}

a=\frac{27.78-0}{9.6}

a=\frac{27.78}{9.6}

a=2.89m/s^{2}

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Answer:

The cat

Explanation:

1) You need to find how many meters per second each thing is sprinting, so you can divide the meters by seconds for each.

\frac{240}{30} = 8 m/s\\\frac{100}{9.5} = around  10.5 m/s

2) Per second, the sprinter is able to achieve 8 meters, while the cat can do around 10.5 meters. 10.5 is greater than 8, making the cat faster than the sprinter.

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2 years ago
Witch best describes the storage of the genetic code
natulia [17]

Answer:

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5 0
3 years ago
A gas has a pressure of 1.34 atm when the temperature is 237K. The gas is then heated until the temperature measures 312K. What
alexandr1967 [171]

The answer for the following question is answered below.

  • <em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>

Explanation:

Given:

Initial pressure of the gas = 1.34 atm

Initial temperature of the gas = 273 K

final temperature of the gas = 312 K

To solve:

Final temperature of the gas

We know;

From the ideal gas equation

P × V = n × R × T

So;

from the above equation we can say that

    <em>P ∝ T</em>

     \frac{P}{T} = constant  

     \frac{P_{1} }{P_{2} } = \frac{T_{1} }{T_{2} }

Where;

P_{1} = initial pressure of a gas

P_{2} = final pressure of a gas

T_{1} = initial temperature of a gas

T_{2} = final temperature of  a gas

    P_{2} = \frac{1.34*312}{237}

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6 0
2 years ago
Which set of coefficients will balance this chemical equation?
Montano1993 [528]

Answer:

Option B is correct = 1,3

Explanation:

Chemical equation:

C₂H₄ + O₂     →    CO₂ + H₂O

Balanced chemical equation:

C₂H₄ + 3O₂     →    2CO₂ + 2H₂O

Step 1:

Left side                      Right side

C = 2                           C = 1

H = 4                           O = 3

O = 2                           H = 2

Step 2:

C₂H₄ + O₂     →    2CO₂ + H₂O

Left side                      Right side

C = 2                           C = 2

H = 4                           O = 5

O = 2                           H = 2

Step 3:

C₂H₄ + O₂     →    2CO₂ + 2H₂O

Left side                      Right side

C = 2                           C = 2

H = 4                           O = 6

O = 2                           H = 4

Step 4:

C₂H₄ + 3O₂     →    2CO₂ + 2H₂O

Left side                      Right side

C = 2                           C = 2

H = 4                           O = 6

O = 6                           H = 4

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Explanation:

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