All categories

3 years ago

How do i design a controlled experiment to appropriately test a hypothesis?

Chemistry

1 answer:

Virty [35]3 years ago

3 0

Answer:

you need only one independent variable because if not, you wont know what factors have changed your experiment.

Explanation:

You might be interested in

Which element most likely has the same number of valence electrons as silicon(si)?

Blizzard [7]

Answer:

Carbon, germanium, tin and lead.

Explanation:

The silicon is belong to the carbon family. There are five elements in carbon family carbon, silicon, germanium, tin and lead. These five elements are present in same group i.e group fourteen. The elements present in same group have same number of valance electrons.

For example.

Carbon electronic configuration:

C₆ = [He] 2s² 2p²

Silicon electronic configuration:

Si₁₄ = [Ne] 3s² 3p²

Germanium electronic configuration:

Ge₃₂ = [Ar] 3d¹⁰ 4s² 4p²

Tin electronic configuration:

Sn₅₀ = [Kr] 4d¹⁰ 5s² 5p²

Lead electronic configuration:

Pb₈₂ = [Xe] 4f¹⁴ 5d¹⁰ 6s² 6p²

we can see that in case of all elements there are four valance electrons, which are equal to the valance electrons of silicon.

7 0

3 years ago

DO NOT ANSWER IF YOU DO NOT KNOW WHAT TO DO

Mice21 [21]

Answer:

im gunna save my answer so no one can take it:)

Explanation:

I tried my best

4 0

3 years ago

Read 2 more answers

What kind of igneous rock usually contains large crystals?

sladkih [1.3K]

Intrusive Igneous Rocks.

8 0

3 years ago

What would be the oxidation number of the atoms in these compounds?

sashaice [31]

Answer:

Oxidation state] is defined as the charge an atom might be imagined to have when electrons are counted according to an agreed-upon set of rules:

The oxidation state of a free element (uncombined element) is zero for a simple (monoatomic) ion, the oxidation state is equal to the net charge on the ion.

Hydrogen has an oxidation state of 1 and oxygen has an oxidation state of −2 when they are present in most compounds. (Exceptions to this are that hydrogen has an oxidation state of −1 in hydrides of active metals, e.g. LiH, and oxygen has an oxidation state of −1 in peroxides, e.g. H2O2 the algebraic sum of oxidation states of all atoms in a neutral molecule must be zero, while in ions the algebraic sum of the oxidation states of the constituent atoms must be equal to the charge on the ion.

The same is written in my textbook. But how am I supposed to find the ox. number of an atom, which is in compound like K2UO4?

8 0

3 years ago

Nitroglycerin, used both in medicine and as an explosive, can be prepared by the carefully controlled reaction of glycerol (C3H8

vesna_86 [32]

The mass of nitric acid (HNO₃) required for the production of 2.8 g of nitroglycerin? (C₃H₅N₃O₉) is 2.33 g

We'll begin by calculating the mass of HNO₃ that reacted and the mass of C₃H₅N₃O₉ produced from the balanced equation. This can be obtained as follow:

C₃H₈O₃ + 3HNO₃ —> C₃H₅N₃O₉ + 3H₂O

Molar mass of HNO₃ = 1 + 14 + (16×3)

= 1 + 14 + 48

= 63 g/mol

Mass of HNO₃ from the balanced equation = 3 × 63 = 189 g

Molar mass of C₃H₅N₃O₉ = (12×3) + (1×5) + (14×3) + (16 × 9)

= 36 + 5 + 42 + 144

= 227 g/mol

Mass of C₃H₅N₃O₉ from the balanced equation = 1 × 227 = 227 g

<h3>SUMMARY:</h3>

From the balanced equation above,

227 g of C₃H₅N₃O₉ were produced by 189 g of HNO₃.

Finally, we shall determine the mass of HNO₃ that will produce 2.8 g of C₃H₅N₃O₉. This can be obtained as follow:

From the balanced equation above,

227 g of C₃H₅N₃O₉ were produced by 189 g of HNO₃.

Therefore,

2.8 g of C₃H₅N₃O₉ will be produce by = $\frac{2.8 * 189}{227} \\\\$ = 2.33 g of HNO₃

Thus, the mass of nitric acid (HNO₃) required for the production of 2.8 g of nitroglycerin? (C₃H₅N₃O₉) is 2.33 g

Learn more: brainly.com/question/24918379

3 0

2 years ago