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Katen [24]
2 years ago
14

If you hadn't added quite enough hydrochloric acid to consume all the magnesium metal, what would be the effect of this error on

the percent yield in your experiment? Would the actual yield ( and thus the percent yield) be erroneously high, low, or be unaffected by not adding enough HCl? Explain
Chemistry
1 answer:
sweet-ann [11.9K]2 years ago
8 0

If enough HCl is not added, the percent yield will be lower as all the magnesium metal has not reacted with HCl.

<h3>What is percent yield of a reaction?</h3>

The percent yield of a reaction is the ratio of the actual yield and the expected yield expressed as a percentage.

  • Percent yield = actual yield/expected yield × 100%

The reaction between magnesium metal and HCl liberates hydrogen gas and forms magnesium chloride salt.

If enough HCl was not added to react with all the magnesium metal, the actual yield will be lower.

Hence, percent yield will be lower as well.

Therefore, the percent yield will be lower if all the magnesium metal has not reacted with HCl.

Learn more about percent yield at: brainly.com/question/10046114

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The standard reduction potentials of lithium metal and chlorine gas are as follows: Reaction Reduction potential (V) Li+(aq)+e−→
kakasveta [241]

Under standard conditions :

E(cell) = E(cathode) - E(anode)

Note : cathode has the larger numeric value and anode has the smaller. Therefore

E(cell) = +1.36V - ( -3.04V)

= 1.36 + 3.04

= +4.40V

6 0
3 years ago
A sample of solid NH 4HS is placed in a closed vessel and allowed to equilibrate. Calculate the equilibrium partial pressure (at
UNO [17]

Answer:

The answer to the question is

The equilibrium partial pressure (atm) of ammonia, assuming that some solid NH₄HS remains 0.26 atm.

Explanation:

To solve the question, we write out the chemical equation as follows

NH₄HS (s) ⇄ NH₃ (g) + H₂S (g)

From the above equation, it is observed that only the gaseous products contribute to the partial pressure

Kp =PNH₃·PH₂S where at Kp = 0.070 and PNH₃, PH₂S are the partial pressures of the gases

However since the number of moles of both gases are equal, therefore by Avogadro's law PNH₃ = PH₂S

Then PNH₃  = √(0.07) = PH₂S = 0.2645 atm. ≅ 0.26 atm.

5 0
4 years ago
In class, it was mentioned that at 25 °C, the pH of pure water is 7.00 becuase Kw = 1.0 × 10−14. At other temperatures, the pH v
ivanzaharov [21]

Answer:

Kw = 2.88 × 10⁻¹⁵

Explanation:

Let's consider the dissociation of water.

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)

The equilibrium constant Kw is:

Kw = [H⁺].[OH⁻]

If pH = 7.27, we can find [H⁺]:

pH = -log [H⁺]

H⁺ = anti log (-pH) = anti log (-7.27) = 5.37 × 10⁻⁸ M

According to the balanced equation, 1 mole of H⁺ is produced per mole of OH⁻. So, [H⁺] = [OH⁻] = 5.37 × 10⁻⁸ M

Then,

Kw = [H⁺].[OH⁻]= (5.37 × 10⁻⁸)² = 2.88 × 10⁻¹⁵

5 0
4 years ago
Which of the following is an example of a PHYSICAL change?
Nezavi [6.7K]

Rust on a nail is a chemical change.

Ice melting IS a physical change. Ice is made of water, when you melt ice its still water. Just in a different physical state.

3 0
3 years ago
4/5(2x 5)−4=1
uysha [10]
 5/8=0.625 4/5=.8


5/8 because 5/8=0.625 and because its 2x you multiply 0.625 by 2=1.25 then you do 1.25+5=6.25 4/5=.8    6.25 times .8=5 5-4=1   


X=5/8 or 0.625

5 0
4 years ago
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