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tigry1 [53]
3 years ago
5

Use the drop-down menus to complete the statements

Chemistry
1 answer:
Kipish [7]3 years ago
3 0

Answer:

First one: group

Second one: period

Third one: number of valence electrons

Last one: increases

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For each pair of gases, select one that most likely has the highest rate of effusion. Use the periodic table if necessary
brilliants [131]
You will do the highest one i think
4 0
3 years ago
Read 2 more answers
You have a 15.0 gram sample of gold at 20.0°C. How much heat does it take to raise the temperature to 100.0°C?
Nadusha1986 [10]

Answer:

=154.8 J

Explanation:

The rise in temperature is contributed by the change in temperature.

Change in enthalpy = MC∅,  where M is the mass of the substance, C is the specific heat capacity and ∅ is the change in temperature.

Change in temperature = 100.0°C-20.0°C=80°C

ΔH=MC∅

The specific heat capacity of gold= 0.129 J/g°C

ΔH= 15.0g×0.129J/g°C×80°C

=154.8 J

7 0
3 years ago
Covalent bonds can occur where atoms share one or more pairs of electrons. Which of the following would form a double covalent b
mojhsa [17]

Answer:

The answer to your question is: CO2

Explanation:

The information given is correct, Covalent bonds occur when atoms share one or more pairs of electrons, but also, covalent bonds occur with nonmetals, then,

a.NaCl     This elements form an ionic bond, so this option is incorrect.

b.Cl2      Here there are two non metals  but the form one single covalent bond, so this option is incorrect.

c.CO2  Carbon dioxide forms 2 double covalent bonds.

d.NH3 ammonium only forms single covalent bonds

6 0
3 years ago
How many grams of oxygen are required too burn 8.8g of c3h8?
hichkok12 [17]
From the balanced equation: 
<span>1mol C3H8 requires 5mol O2 for combustion </span>
<span>Molar mass C3H8 = 44g/mol </span>
<span>8.8g C3H8 = 8.8/44 = 0.2mol C3H8 </span>
<span>This will require 5*0.2 = 1.0mol O2 </span>
<span>Molar mass O2 = 32g/mol </span>
<span>Therefore 32g of O2 required.


</span>
4 0
3 years ago
what is the density of mercury if 205 mL has a mass of 2790 g; round your answer to the nearest 0.1 g/mL
kherson [118]
D = m / V

D = 2790 g / 205 mL

D = 13.60 g/mL
4 0
3 years ago
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