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tigry1 [53]
3 years ago
5

Use the drop-down menus to complete the statements

Chemistry
1 answer:
Kipish [7]3 years ago
3 0

Answer:

First one: group

Second one: period

Third one: number of valence electrons

Last one: increases

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What best describes the collision between ideal gas molecules
Alika [10]
An ideal gas is defined as one in which all collisions between atoms or molecules are perfectly eleastic and in which there are no intermolecular attractive forces. One can visualize it as a collection of perfectly hard spheres which collide but which otherwise do not interact with each other.

Happy to help
6 0
3 years ago
Determine the mass in grams of Avogadro's number of C12H22O11
Allushta [10]

Answer:

2.059524x10^26 if im not wrong

Explanation:

avogadro's number is 6.022x10^23

5 0
2 years ago
What is the wavelength of light with 2.89 x 10-19 J of energy? (The speed of
Alika [10]

Let's see

\\ \rm\rightarrowtail E=hv

\\ \rm\rightarrowtail E=\dfrac{hc}{\lambda}

  • lambda is wavelength
  • h is Planck constant
  • c is velocity of sound in air
  • E in energy

\\ \rm\rightarrowtail \lambda=\dfrac{hc}{E}

\\ \rm\rightarrowtail \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{2.89\times 10^{-19}}

\\ \rm\rightarrowtail \lambda=6.878\times 10^{-7}m

\\ \rm\rightarrowtail \lambda=68.8\mu m

3 0
2 years ago
A. Calculate the empirical formula of a molecule with percent compositions: 55.3% potassium (K), 14.6% phosphorus (P), and 30.1%
Otrada [13]
The way you calculate the empirical formula is to firstly assume 100g. To find each elements moles you take each elements percentage listed, times it by one mole and divide it by its atomic mass. (ex: moles of K =55.3g x 1 mole/39.1g, therefore there is 1.41432225 moles of Potassium) Once you’ve completed this for every element you list each elements symbol beside it’s number of moles and divide by the smallest number because it can only go into its self once. After you’ve done this, you’ve found your empirical formula, which is the simplest whole number ratio of atoms in a compound. I’ve added an example of a empirical question I completed last semester :)

6 0
3 years ago
Read 2 more answers
Challenge question: This question is worth 6 points. As you saw in problem 9 we can have species bound to a central metal ion. T
Llana [10]

Answer:

A

Explanation:

Iron has the ground state electronic configuration [Ar]3d64s2

Fe2+ has the electronic configuration [Ar]3d6.

In an octahedral crystal field, there are two sets of degenerate orbitals; the lower lying three t2g orbitals, and the higher level two degenerate eg orbitals. Strong field ligands cause high octahedral crystal field splitting, there by separating the two sets of degenerate orbitals by a tremendous amount of energy. This energy is much greater than the pairing energy required to pair the six electrons in three degenerate orbitals. Since CN- is a strong field ligand, it leads to pairing of six electrons in three degenerate orbitals

3 0
3 years ago
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