At sea level, a kilogram welghs approximately 2 pounds 10 pounds 5 pounds 1 pound

What is observed when magnesium is reacted with hydrochloric acid? choose all that apply

Zanzabum

It is observed that when magnesium reacts with hydrochloric acid, it produces visible bubbles of hydrogen gas.

A vigorous reaction will occur giving rise of heat as it is an exothermic reaction. If heat is applied then it should be more vigorous.

Reaction is as follows:

Mg(s) + HCl (aq) --> MgCl2 (aq) + H2(g)

Magnesium reacts easily with HCl to produce H2 gas and magnesium ions, Mg2+, and heat. The reaction is exothermic, so it heats up quickly.

Mg(s) + HCl (aq) --> MgCl2(aq) + H2(g)

The net ionic equation :

Mg(s) + 2H+ --> Mg2 + H2(g)

If water is removed from the solution then white crystals of Mgcl2 is obtained.

Or in simple words,

2Mg + 2HCl -> 2Mg+ + 2Cl- + H2(gas)

The magnesium is attacked by the hydrochloric acid resulting in the magnesium dissolving into the solution resulting in a solution of magnesium chloride in hydrochloric acid and the production of hydrogen gas.

Learn more about magnesium here : brainly.com/question/5759562

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3 0

1 year ago

1) a solution with a hyrdrogen ion concentration of 1x10^-4 moles/liter would have a PH of what?

lana66690 [7]

Answer:

pH = -log(concentration of hydro.gen ion)

1. When con. of H ion is 1*10-4 mol/L

pH = -log(1*10-4) = -(-4) = 4

2. A solution with a pH of 1*10-12mol/L

pH = -log (1*10-12) = -(-12) = 12

The pH is 12 and the solution is basic or alkaline

3.A solution with a pH of 6 has the concentration of

pH = -log (H+)

(H+) = arc log -pH

(H+) = 1*10-6

Explanation:

7 0

2 years ago

Draw the addition product formed when one equivalent of hcl reacts with the following diene.

pashok25 [27]

Answer:

Major Product = 4-chloro-4-methylcyclohex-1-ene

Explanation:

Alkene are the class of organic compounds which contain one or more double bonds between two carbon atoms. Alkenes are considered most reactive among the unsaturated hydrocarbons and they undergo addition reactions due to high electron density around the double bonds.

In given question it is written that we are provided with one equivalent of HCl while, our compound contains two double bonds (diene) so in selected starting material the HCl will be added across (hydrohalogenation reaction) the substituted double bond because it will give a more stable carbocation (tertiary carbocation) during the reaction course. Hence, as shown in reaction scheme 4-chloro-4-methylcyclohex-1-ene will be the major product.

5 0

2 years ago

A gas balloon has a volume of 80.0 mL at 300K, and a pressure of 50.0 kPa. If the pressure changes to 80 kPa and the temperature

fomenos

Answer: The new volume is 53.3 ml

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 50.0 kPa

$P_2$ = final pressure of gas = 80.0 kPa

$V_1$ = initial volume of gas = 80.0 ml

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $300K$

$T_2$ = final temperature of gas = $320K$

Now put all the given values in the above equation, we get:

$\frac{50.0\times 80.0}{300}=\frac{80.0\times V_2}{320}$

$V_2=53.3ml$

The new volume is 53.3 ml

4 0

2 years ago

The ammonia molecule in the diagram has the observed bond orientation because ...

aivan3 [116]

Answer:

Nitrogen has four pairs of electrons: 3 bonds and 1 lone pair in the valence shell;
Electrons repel one another based on the VSEPR theory;
Nitrogen has a total of 7 protons (its atomic number is 7) in its nucleus.

Explanation:

The shape and the bond orientation of molecules and ions are both explained by the valences shell electron pair repulsion theory (VSEPR).

Ammonia, $NH_3$ , is a molecule which contains three N-H bonds, as well as one lone pair on nitrogen. According to the VSEPR theory, molecules try to acquire a shape which would minimize the repulsion exhibited by the electron clouds present, that is, between the bonding (shared in a bond) and non-bonding (lone pair) electrons.

In VSEPR, our main step is to calculate the steric number, this is the sum of the number of bonds (ignoring the multiplicity of any bond) and the lone pairs on a central atom. In ammonia, we have 3 bonds and 1 lone pair, totaling to a steric number of 4. A steric number of 4 without any lone pairs on a central atom and just bonds would yield a tetrahedral shape with bond angles of $109.5^o$ .

Now, in this case, since we have a lone pair instead of a bond, it is repelling stronger decreasing the bond angles to about $107^o$ .

The greater the number of lone pairs, the lower the angle becomes.

To summarize:

Nitrogen has four pairs of electrons: 3 bonds and 1 lone pair in the valence shell;
Electrons repel one another based on the VSEPR theory;
Nitrogen has a total of 7 protons (its atomic number is 7) in its nucleus.

3 0

3 years ago