Answer:
x > -1
Step-by-step explanation:
-3x + 3< 6
-3x < 3
x > -1
Hope it helped !
Adriel
Answer: the answer would be 64
Step-by-step explanation:
What are you looking for?
Problem:
find line perpendicular to 4x+7y+3=0 passing through (-2,1).
Solution:
We will first find the general form of the perpendicular line.
The perpendicular line has the form
7x-4y+k=0 .........................(1)
by switching the coefficients of x and y, and switching the sign of one of the two coefficients. This way, the slope of (1) multiplied by that of the original equation is -1, a condition that the two lines are perpendicular. The value of k is to be determined from the given point (-2,1).
To find k, we substitute x=-2, y=1 into equation (1) and solve for k.
7(-2)-4(1)+k=0
=>
k=14+4=18
Therefore the required line is
7x-4y+18=0
Answer:
The result should be:

Step-by-step explanation:
-The equation of a circle:
where the center is
, the point
and the radius known as
.
-Use the center (6,8) and the point (-1,4) for this equation:

-Then, you solve for the radius and get the equation:






-Result:
