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3 years ago

7w/4+3=9w/10+6 I really need help on this

Mathematics

1 answer:

allochka39001 [22]3 years ago

3 0

Answer:

w=3 9\17

Step-by-step explanation:

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sesenic [268]

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2 years ago

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Kobe wants to organize his toys. His box has a width 2 2/3 feet, length 3 1/3 feet, and height 2 1/3 feet?

Tanya [424]

Answer:

Cubic feet = Length (3 1/3 feet) x Width (2 2/3 feet) x Height (2 1/3 feet)

Step-by-step explanation:

3 1/3 x 2 2/3 x 2 1/3 = approximately 20.74 cubic feet

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2 years ago

A college writing seminar increased its size by 50\PP, percent from the first to the second day. If the total number of students

Jobisdone [24]

Answer: There were 10 students in the class on the first day.

Step-by-step explanation:

Let x be the number of students of the first day.

Given: A college writing seminar increased its size by 50 percent from the first to the second day.

i.e. Number of students on second day = (Number of students on first day)+(50% of Number of students on first day)

= x +50% of x

= x+0.50x

= (1.50)x

=1.50x

Since, it is given that the total number of students in the seminar on the second day was 15.

i.e. $1.50x=15$

$\Rightarrow\ x=\dfrac{15}{1.5}\Rightarrow\ x=\dfrac{150}{15}\\\\\Rightarrow\ x=10$

Hence, there were 10 students in the class on the first day.

7 0

3 years ago

Gary wrote the comparison below.

scoray [572]

Answer:

what box?

Step-by-step explanation:

5 0

2 years ago

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(c). Under a set of controlled laboratory conditions, the size of the population P of a certain bacteria culture at time t (in s

Bezzdna [24]

(i) Since P(t) gives the population of the culture after t seconds, the population after 1 second is

P(1) = 3•1² + 3e¹ + 10 = 13 + 3e ≈ 21.155

In Mathematica, it's convenient to define a function:

P[t_] := 3t^2 + 3E^t + 10

(E is case-sensitive and must be capitalized. Alternatively, you could use Exp[t]. You can also specify that the argument t must be non-negative by entering a condition via P[t_ ;/ t >= 0], but that's not necessary.)

Then just evaluate P[1], or N[P[1]] or N <at symbol> P[1] or P[1] // N to get a numerical result.

(ii) The average rate of change of P(t) over an interval [a, b} is

(P(b) - P(a))/(b - a)

Then the ARoC between t = 2 and t = 6 is

(P(6) - P(2))/(6 - 2) ≈ 321.030

In M,

(P[6] - P[2])/(6 - 2)

and you can also include N just as before.

(iii) You want the instantaneous rate of change of P when t = 60 (since 1 minute = 60 seconds). Differentiate P :

P'(t) = 6t + 3e^t

Evaluate the derivative at t = 60 :

P'(60) = 6•60 + 3e⁶⁰ = 360 + 3e⁶⁰

The approximate value is quite large, so I'll just leave its exact value.

In M, the quickest way would be P'[60], or you can differentiate and replace (via ReplaceAll or /.) t with 60 as in D[P[t], t] /. t -> 60.

5 0

2 years ago