Answer:
0.1333 or 
Step-by-step explanation:
The attached image contains the steps.
Answer: The dimensions are: " 1.5 mi. × ³⁄₁₀ mi. " .
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{ length = 1.5 mi. ; width = ³⁄₁₀ mi. } .
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Explanation:
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Area of a rectangle:
A = L * w ;
in which: A = Area = (9/20) mi.² ,
L = Length = ?
w = width = (1/5)*L = (L/5) = ?
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A = L * w ; we want to find the dimensions; that is, the values for
"Length (L)" and "width (w)" ;
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Plug in our given values:
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(9/20) mi.² = L * (L/5) ; in which: "w = L/5" ;
→ (9/20) = (L/1) * (L/5) = (L*L)/(1*5) = L² / 5 ;
↔ L² / 5 = 9/20 ;
→ (L² * ? / 5 * ?) = 9/20 ?
→ 20÷5 = 4 ; so; L² *4 = 9 ;
↔ 4 L² = 9 ;
→ Divide EACH side of the equation by "4" ;
→ (4 L²) / 4 = 9/4 ;
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to get: → L² = 9/4 ;
Take the POSITIVE square root of each side of the equation; to isolate "L" on one side of the equation; and to solve for "L" ;
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→ ⁺√(L²) = ⁺√(9/4) ;
→ L = (√9) / (√4) ;
→ L = 3/2 ;
→ w = L/5 = (3/2) ÷ 5 = 3/2 ÷ (5/1) = (3/2) * (1/5) = (3*1)/(2*5) = 3/10;
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Let us check our answers:
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(3/2 mi.) * (3/10 mi.) =? (9/20) mi.² ??
→ (3/2)mi. * (3/10)mi. = (3*3)/(2*10) mi.² = 9/20 mi.² ! Yes!
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So the dimensions are:
Length = (3/2) mi. ; write as: 1.5 mi.
width = ³⁄₁₀ mi.
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or; write as: " 1.5 mi. × ³⁄₁₀ mi. " .
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Use a system of equations
C+P=1132
3P=C
Substitute C in first equation as
3P+P=1132
Simplify
4P=1132
Solve
P=1132/4
P=283
NOW SOLVE FOR C SUBSTITUTING P VALUE IN FIRST EQUATION
C+283=1132
C=1132-283
C=849
Printer = 283$
Computer = 849$
length = 8ft
height = 4 in
width = w ft --> u looking for this
convert in to ft for the height:
4 in (1 ft / 12 in) = 1/3 ft
You know that:
1 cubic yard = $ 98
? cubic yard = $58.07
Solve for ? cubic yard:
? cubic yard = 58.07/98 = 0.592551
convert this in cubic feet:
1 yard = 3 feet
0.59255 cubic yard (27 cubic ft/1 cubic yard) = 15.99887755 cubic ft
Now solve for the width:
length x width x height = ? cubic ft.
width = ? cubic ft / (length x height) =15.99887755 cubic ft/[(8ft)(1/3 ft )] = 5.999579082 ft
approx 6 ft