Answer:
Step-by-step explanation:
I don't see Wen's work, but I'll show you mine!
We can create a set of coordinates for each of these sets of data, where x is the time in hours, and y is the number of degrees in Fahrenheit.
At time 0, the temp is 0: (0, 0)
5.75 hours late, the temp is -15.5: (5.75, -15.5)
We can find the change in temp per hour by using the slope formula, since slope is, after all, the rate at which something is changing.
That is rounded to the tenths place from -2.695652174 so you can round it however you need. What the interpretation of this number is is that temp is falling at a rate of 2.7 degrees F per hour.
Answer:
17
Step-by-step explanation:
Answer:
Step-by-step explanation:
I will just change
For
Also, note that sine and cosine function don't have asymptotes.
The vertical asymptotes of cosecant occur every
It happens because the cosecant function is undefined for those values.
The cotangent function has asymptotes located at every integer multiple of .
On the other hand, the vertical asymptotes of tangent function occur at:
It happens because the tangent function is undefined for those values.
Answer:
A translation (9 units) to the left will result in a function that is neither even nor odd
Step-by-step explanation:
With horizontal translation to the left, we have;
h(x) = 12(x - 9)⁸ + 49
Which gives;
h(x) = 12(x - 9)⁸ + 49 = 12(x⁸ - 72x⁷ + 2268x⁶ - 40824x⁵ + 459270x⁴ -3306744x³ + 14880348x² - 38263752x + 43046721) + 49
For x = 1, we get;
h(x) = 201326641
When we replace x by -x, we get;
h(x) = 12(-x - 9)⁸ + 49 = 12(x⁸ + 72x⁷ + 2268x⁶ + 40824x⁵ + 459270x⁴ + 3306744x³ + 14880348x² + 38263752x + 43046721) + 49
For x = 1, we get;
h(x) = 1200000049
Therefore a translation 9 units to the left will result in a function that is neither even nor odd.