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2 years ago

Why wasn’t sodium hydroxide used in the synthesis of divanillyl oxalate, instead of triethylamine?

Chemistry

2 answers:

kupik [55]2 years ago

4 0

Sodium hydroxide wasn't used in the synthesis of divanillyl oxalate because it's a strong base.

<h3>What is sodium hydroxide?</h3>

It should be noted that sodium hydroxide simply means a corrosive cystaline solid which readily absorbs moisture until it dissolves.

In this case, sodium hydroxide wasn't used in the synthesis of divanillyl oxalate because it's a strong base and will decrease the yield of the product.

Learn more about sodium hydroxide on:

brainly.com/question/27072350

ValentinkaMS [17]2 years ago

4 0

Divanillyl oxalate is a chemical that is produced by triethylamine. Sodium hydroxide is not used in its synthesis as it is a strong base.

<h3>What is sodium hydroxide?</h3>

Sodium hydroxide or caustic soda is an ionic compound with ions of sodium and hydroxide. The formula is shown as, $\rm NaOH$ . It is crystalline and absorbs moisture from the surrounding.

It is not used in the synthesis of divanillyl oxalate as it is a strong base with pH 14 that affects the yield of the product in the reaction.

Therefore, sodium hydroxide is not used in the synthesis reaction.

Learn more about sodium hydroxide here:

brainly.com/question/15456619

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ideal gas law: PV = nRT so ..... V = PV/(RT) 

Initial number of moles of Cl, n = 0.943*5.11/(0.08206 × 286) mol = 0.2053 moles.

We know the molar mass of K (potassium) = 39.0 g/mol 
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The Initial number of moles of K = 29.0 g/(39.0 g/mol) = 0.7436 moles

Find the balanced equation for the reaction : 2K + Cl2 → 2KCl 
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So after the reaction, the amount of K needed = (0.2053 mol) × 2 = 0.4106 mol which is less than 0.7436 mol 

This means that K is in excess but Cl completely reacts. 

 So we know the mole ratio is Cl:KCl = 1 : 2

Number of moles of Cl (completely) reacted = 0.2053 mol which means the number of moles of KCl formed = (0.2053 mol) × 2 = 0.4106 mol 

Molar mass of KCl = (39.0 + 35.5) g/mol = 74.5 g/mol 
Mass of KCl formed = 0.4106 mol * 74.5 g/mol = 30.6 g

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