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Oksanka [162]
2 years ago
9

Why wasn’t sodium hydroxide used in the synthesis of divanillyl oxalate, instead of triethylamine?

Chemistry
2 answers:
kupik [55]2 years ago
4 0

Sodium hydroxide wasn't used in the synthesis of divanillyl oxalate because it's a strong base.

<h3>What is sodium hydroxide?</h3>

It should be noted that sodium hydroxide simply means a corrosive cystaline solid which readily absorbs moisture until it dissolves.

In this case, sodium hydroxide wasn't used in the synthesis of divanillyl oxalate because it's a strong base and will decrease the yield of the product.

Learn more about sodium hydroxide on:

brainly.com/question/27072350

ValentinkaMS [17]2 years ago
4 0

Divanillyl oxalate is a chemical that is produced by triethylamine. Sodium hydroxide is not used in its synthesis as it is a strong base.

<h3>What is sodium hydroxide?</h3>

Sodium hydroxide or caustic soda is an ionic compound with ions of sodium and hydroxide. The formula is shown as, \rm NaOH. It is crystalline and absorbs moisture from the surrounding.

It is not used in the synthesis of divanillyl oxalate as it is a strong base with pH 14 that affects the yield of the product in the reaction.

Therefore, sodium hydroxide is not used in the synthesis reaction.

Learn more about sodium hydroxide here:

brainly.com/question/15456619

#SPJ4

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At equilibrium, the concentrations in this system were found to be [N2]=[O2]=0.200 M and [NO]=0.400 M.
Kipish [7]

Answer:

The concentration in equilibrium of NO is 0,550M.

Explanation:

For the reaction:

N₂(g) + O₂(g) ⇄ 2NO

The equilibrium constant is defined as:

k = [NO]² / [N₂][O₂] <em>(1)</em>

Replacing for the concentrations in equilibrium:

k = (0,400M)² / (0,200M)(0,200M)

<em>k = 4,000</em>

If you add more NO until 0,700M, the equilibrium concentrations will be:

[NO] = 0,700M-2x

[N₂] = 0,200M+x

[O₂] = 0,200M+x

Replacing in (1)

4,000 =  (0,700M-2x)² / (0,200M+x)²

4,000 =  4x²- 2,8x + 0,49 / x² + 0,4x + 0,04

4x² + 1,6x + 0,16 = 4x²- 2,8x + 0,49

4,4x = 0,33

x = 0,075M

That means that concentration in equilibrium of NO is:

[NO] = 0,700M - 2×0,075M = <em>0,550M</em>

I hope it helps!

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