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NNADVOKAT [17]
3 years ago
8

What type of mixture is 100 ml of water with a little bit of salt?

Chemistry
1 answer:
gregori [183]3 years ago
3 0
<span>What type of mixture is 100 ml of water with a little bit of salt?</span>
A solution

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Consider a transition of the electron in the hydrogen atom from n=3 to n=7.
kow [346]

<u>Answer:</u>

<u>For a:</u> The wavelength of light is 1.005\times 10^{-6}m

<u>For b:</u> The light is getting absorbed

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the wavelength of light, we use Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 1.097\times 10^7m^{-1}

n_f = Higher energy level = 7

n_i= Lower energy level = 3

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{3^2}-\frac{1}{7^2} \right )\\\\\lambda =1.005\times 10^{-6}m

Hence, the wavelength of light is 1.005\times 10^{-6}m

  • <u>For b:</u>

There are two ways in which electrons can transition between energy levels:

  1. <u>Absorption spectra:</u> This type of spectra is seen when an electron jumps from lower energy level to higher energy level. In this process, energy is absorbed.
  2. <u>Emission spectra:</u> This type of spectra is seen when an electron jumps from higher energy level to lower energy level. In this process, energy is released in the form of photons.

As, the electron jumps from lower energy level to higher energy level. The wavelength is getting absorbed.

6 0
3 years ago
Uniones que se dan entre atomo y moleculas
lesya [120]

Answer:

khbfd skjb skbusf szkbs

Explanation:jdfh sms kok

6 0
3 years ago
Write the Henderson-Hasselbalch equation for a solution of formic acid. Calculate the quotient [HCO2]/[HCO2H] at (a) pH 3.000; (
Elena L [17]

Answer:

a. 0.182

b. 1.009

c. 1.819

Explanation:

Henderson-Hasselbach equation is:

pH = pKa + log [salt / acid]

Let's replace the formula by the given values.

a. 3 = 3.74 + log [salt / acid]

3 - 3.74 = log [salt / acid]

-0.74 = log [salt / acid]

10⁻⁰'⁷⁴ = 0.182

b. 3.744 = 3.74 + log [salt / acid]

3.744 - 3.74 = log [salt / acid]

0.004 = log [salt / acid]

10⁰'⁰⁰⁴ = 1.009

c. 4 = 3.74 + log [salt / acid]

4 - 3.74 = log [salt / acid]

0.26 = log [salt / acid]

10⁰'²⁶ = 1.819

3 0
3 years ago
My teacher is grading this soon can someone help me ASAP!
Stolb23 [73]

10. You demonstrated the difference in density of the two objects. It is a physical property.

11. First calculate the density for all of them: density = mass/volume

Density:

A. 5/6 g/ml

B. 10/9 g/ml

C. 15/16 g/ml

D. 20/10 g/ml

If the density of the substance is higher than the density of the substance it is put in, then it will sink. So substances B and D will sink in water, as their densities are higher than 1 g/ml.

12. Ammonia weighs less than water does-- for example, the weight of 8 gallons of ammonia will be equivalent to the weight of 5 gallons of water.

Hope this helped!

3 0
3 years ago
A(n) _____ is a natural object that orbits another object in the solar system besides the Sun.
Stolb23 [73]
The answer is the moon

4 0
3 years ago
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