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3 years ago

How many moles of H2SO4 are needed to completely neutralize 0.0164 mol KOH

Chemistry

2 answers:

Vanyuwa [196]3 years ago

8 0

0.0082 You have to equal out the amount of concentration with the unknown

777dan777 [17]3 years ago

4 0

Answer:0.0082 moles of $H_2SO_4$ will be needed to neutralize the 0.0164 KOH.

Explanation:

$H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O$

2 moles of Potassium hydroxide neutralizes 1 mole of sulfuric acid.

Then 0.0164 moles of potassium hydroxide will neutralize $\frac{1}{2}\times 0.0164 moles$ of sulfuric acid that is 0.0082 moles.

$\frac{1}{2}\times 0.0164 moles=0.0082 moles$

0.0082 moles of $H_2SO_4$ will be needed to neutralize the 0.0164 KOH.

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A container has a mixture of NO2 gas and N2O4 gas in equilibrium. The chemical reaction between the two gases is described by th

kondaur [170]

Answer: The most likely partial pressures are 98.7MPa for NO₂ and 101.3MPa for N₂O₄

Explanation: To determine the partial pressures of each gas after the increase of pressure, it can be used the equilibrium constant Kp.

For the reaction 2NO₂ ⇄ N₂O₄, the equilibrium constant is:

Kp = $\frac{P(N_{2}O_{4} )}{P(NO_{2} ^{2}) }$

where:

P(N₂O₄) and P(NO₂) are the partial pressure of each gas.

Calculating constant:

Kp = $\frac{38.8}{61.2^{2} }$

Kp = 0.0104

After the weights, the total pressure increase to 200 MPa. However, at equilibrium, the constant is the same.

P(N₂O₄) + P(NO₂) = 200

P(N₂O₄) = 200 - P(NO₂)

Kp = $\frac{P(N_{2}O_{4} )}{P(NO_{2} ^{2}) }$

0.0104 = $\frac{200 - P(NO_{2}) }{[P(NO_{2} )]^{2}}$

0.0104 $[P(NO_{2} )]^{2}$ + $P(NO_{2} )$ - 200 = 0

Resolving the second degree equation:

$P(NO_{2} )$ = $\frac{-1+\sqrt{9.32} }{0.0208}$

$P(NO_{2} )$ = 98.7

Find partial pressure of N₂O₄:

P(N₂O₄) = 200 - P(NO₂)

P(N₂O₄) = 200 - 98.7

P(N₂O₄) = 101.3

The partial pressures are $P(NO_{2} )$ = 98.7 MPa and P(N₂O₄) = 101.3 MPa

3 0

3 years ago

100 points!! Brainliest if correct!!

snow_tiger [21]

Answer A: CO2

Reason: carbon dioxides formula is CO and the number next to it is the molecules

6 0

3 years ago

Read 2 more answers

The number of particles in 1 mole of hydrogen gas is ________.

ivanzaharov [21]

Hidrogen gas is a diatomic gas, this is H2, which means that one molecule of gas has two atoms (every molecule of hydrogen gas consists in H2).

The particles in gases are the molecules, not atoms.

So, every molecule is a particle, and when you are told that you have 1 mole of hygrogen gas means that you have 1 mole of H2 molecules which is the same that 1 mole of particles.

Therefore, the answer is one mole.

3 0

3 years ago

What is the number of molecules of c2h5oh in a 3m solution that contains 4.00kg h2o?

Veronika [31]

The number of C2H5OH in a 3 m solution that contain 4.00kg H2O is calculate as below

M = moles of the solute/Kg of water

that is 3M = moles of solute/ 4 Kg
multiply both side by 4

moles of the solute is therefore = 12 moles

by use of Avogadro law constant

1 mole =6.02 x10^23 molecules

what about 12 moles

=12 moles/1 moles x 6.02 x10^23 = 7.224 x10^24 molecules

3 0

3 years ago

How many moles of CH4 are in 148.6 g? Round your answer to two decimal places.

Dafna1 [17]

Answer:

9.29 mol

Explanation:

Given data:

Number of moles = ?

Mass = 148.6 g

Solution:

Number of moles = mass/ molar mass

Molar mass of CH₄ = 16 g/mol

Now we will put the values in formula.

Number of moles = 148.6 g/ 16 g/mol

Number of moles = 9.29 mol

Thus 148.6 g have 9.29 moles.

6 0

3 years ago