How many moles of H2SO4 are needed to completely neutralize 0.0164 mol KOH
2 answers:
0.0082 You have to equal out the amount of concentration with the unknown
Answer:0.0082 moles of
will be needed to neutralize the 0.0164 KOH.
Explanation:

2 moles of Potassium hydroxide neutralizes 1 mole of sulfuric acid.
Then 0.0164 moles of potassium hydroxide will neutralize
of sulfuric acid that is 0.0082 moles.

0.0082 moles of
will be needed to neutralize the 0.0164 KOH.
You might be interested in
Answer:
to protect it from harm
Explanation:
C + H2O -> H2 + CO
n(C) = 15.9/12 = 1.325 (mol)
=> n(H2) = 1.325 mol
We have:
PV = nRT
=> V = (nRT)/P
(R = 22.4/273 = 0.082)
V = (1.325 x 0.082 x 360)/1 = 39.114 (L)
Answer:
A) pH = 2.8
B) pH = 5.5
C) pH = 8.9
D) pH = 13.72
Explanation:
a) [H⁺] = 1.6 × 10⁻³ M
pH = -log [H⁺]
pH = -log [1.6 × 10⁻³ ]
pH = 2.8
b) [H⁺] = 3 × 10⁻⁶
pH = -log [H⁺]
pH = -log [3 × 10⁻⁶ ]
pH = 5.5
c) [OH⁻] = 8.2 × 10⁻⁶
pOH = -log[OH]
pOH = -log[8.2 × 10⁻⁶]
pOH = 5.1
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 5.1
pH = 8.9
d) [OH⁻] = 0.53 M
pOH = -log[OH]
pOH = -log[0.53]
pOH = 0.28
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 0.28
pH = 13.72
population is the number of species living in a given area if this is regarding biology or earth studies :)
Answer:
Chemical Weathering
Explanation:
Took test