Question

How many moles of H2SO4 are needed to completely neutralize 0.0164 mol KOH

Answer 1

0.0082 You have to equal out the amount of concentration with the unknown

Answer 2

Answer:0.0082 moles of $H_2SO_4$ will be needed to neutralize the 0.0164 KOH.

Explanation:

$H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O$

2 moles of Potassium hydroxide neutralizes 1 mole of sulfuric acid.

Then 0.0164 moles of potassium hydroxide will neutralize $\frac{1}{2}\times 0.0164 moles$ of sulfuric acid that is 0.0082 moles.

$\frac{1}{2}\times 0.0164 moles=0.0082 moles$

0.0082 moles of $H_2SO_4$ will be needed to neutralize the 0.0164 KOH.