How many moles of H2SO4 are needed to completely neutralize 0.0164 mol KOH
2 answers:
0.0082 You have to equal out the amount of concentration with the unknown
Answer:0.0082 moles of 
will be needed to neutralize the 0.0164 KOH.
Explanation:
2 moles of Potassium hydroxide neutralizes 1 mole of sulfuric acid.
Then 0.0164 moles of potassium hydroxide will neutralize 
of sulfuric acid that is 0.0082 moles.
0.0082 moles of will be needed to neutralize the 0.0164 KOH.
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Answer:
to protect it from harm
Explanation:
C + H2O -> H2 + CO
n(C) = 15.9/12 = 1.325 (mol)
=> n(H2) = 1.325 mol
We have:
PV = nRT
=> V = (nRT)/P
(R = 22.4/273 = 0.082)
V = (1.325 x 0.082 x 360)/1 = 39.114 (L)
Answer:
A) pH = 2.8
B) pH = 5.5
C) pH = 8.9
D) pH = 13.72
Explanation:
a) [H⁺] = 1.6 × 10⁻³ M
pH = -log [H⁺]
pH = -log [1.6 × 10⁻³ ]
pH = 2.8
b) [H⁺] = 3 × 10⁻⁶
pH = -log [H⁺]
pH = -log [3 × 10⁻⁶ ]
pH = 5.5
c) [OH⁻] = 8.2 × 10⁻⁶
pOH = -log[OH]
pOH = -log[8.2 × 10⁻⁶]
pOH = 5.1
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 5.1
pH = 8.9
d) [OH⁻] = 0.53 M
pOH = -log[OH]
pOH = -log[0.53]
pOH = 0.28
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 0.28
pH = 13.72
population is the number of species living in a given area if this is regarding biology or earth studies :)
Answer:
Chemical Weathering
Explanation:
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