Answer:
-2
Explanation:
carbonate oxifation number is -2
Answer:
83.20 g of Na3PO4
Explanation:
1 mole of Na3PO4 contains 3 moles of Na+.
Mole of Na ion to be prepared = Molarity x volume
= 0.700 x 725/1000
= 0.5075 mole
If 1 mole of Na3PO4 contains 3 moles of Na ion, then 0.5075 Na ion will be contained in:
0.5075/3 x 1 = 0.1692 mole of Na3PO4
mole of Na3PO4 = mass/molar mass = 0.1692
Hence, mass of Na3PO4 = 0.1692 x molar mass
= 0.1692 x 163.94
= 83.20 g.
83.20 g of Na3PO4 will be needed.
Explanation:
The given reaction is as follows.

Value of equilibrium constant is given as
= 4.3 \times 10^{6}[/tex].
Concentration of given species is
= 0.010 M;
= 10.M;
= 0.010 M.
Formula for experimental value of equilibrium constant (Q) is as follows.
Q =
Putting the given concentration as follows.
Q =
Q = 
Q = 
It is known that when Q >
, then reaction moves in the backward direction.
When Q <
, then reaction moves in the forward direction.
When Q =
, then reaction is at equilibrium.
As, for the given reaction Q >
then it means reaction moves in the backward direction.
Thus, we can conclude that the reaction is moving in the backward direction, that is, right to left to reach the equilibrium.
Moles= mass\ relative formula mass(Ar)
moles of zinc= 7.9/30= 0.263
so we have 0.263 moles of zinc, and you need twice the amount of chlorine so therefore 0.526moles of chlorine= 0.526x 17=8.942g of chlorine
i cba to work the rest out but the most reasonable answer is 0.24 mol however if you need to use working outs, use the formula i provided earlier