Using the normal distribution, it is found that she scores less than 128 in 28.1% of her games.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by
.
The proportion of games in which she scores less than 128 is the <u>p-value of Z when X = 128</u>, hence:


Z = -0.58
Z = -0.58 has a p-value of 0.281.
She scores less than 128 in 28.1% of her games.
More can be learned about the normal distribution at brainly.com/question/24663213
#SPJ1