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Valentin [98]
2 years ago
15

When Nayeli goes bowling, her scores are normally

Mathematics
1 answer:
Ber [7]2 years ago
3 0

Using the normal distribution, it is found that she scores less than 128 in 28.1% of her games.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by \mu = 135, \sigma = 12.

The proportion of games in which she scores less than 128 is the <u>p-value of Z when X = 128</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{128 - 135}{12}

Z = -0.58

Z = -0.58 has a p-value of 0.281.

She scores less than 128 in 28.1% of her games.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

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Here, (x1, y1)  =  (6, -4) and (x2, y2)  = (0, 5)

Distance = √[(x2 - x1)² + (y2 - y1)²]

= √[(0 - 6)² + (5 - -4)²]

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Hope this helps!!!!!!!!

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A taste test asks people from Texas and California which pasta they prefer,
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Answer:

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Step-by-step explanation:

We are given that a taste test asks people from Texas and California which pasta they prefer,  brand A or brand B. The table is given in the question.

A person is randomly selected from those tested.

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Also,  P(Texas/brand A)  =  \frac{P(Texas \bigcap Brand A)}{P(Brand A)}

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Therefore, being from Texas and preferring brand A are independent events because P(Texas) ≈ 0.45 and P(Texas/brand A) ≈ 0.45.        

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2 years ago
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