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trasher [3.6K]
3 years ago
10

A solution of a weak acid was tested with the following indicators and the colors noted: Methyl Violet - violet Thymol Blue - ye

llow Methyl Yellow - yellow Congo Red - orange Bromcresol green - green What is the approximate pH of the solution
Chemistry
1 answer:
blsea [12.9K]3 years ago
3 0

pH ranges depending on the solution, for a solution with weak acid pH will be between 4.0-7.0.

<h3>What is pH?</h3>

pH is helps to determine if a solution is acidic or basic in nature.

A pH meter is the instrument that can be used for the measurements.

Methyl orange is used when titrating a strong acid against a weak base.

Therefore, the pH of the solution which is a weak acid will be between 4.0-7.0.

Learn more on pH level here,

brainly.com/question/4137247

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A chemist makes up a solution by dissolving 42.0 g of Mg(NO3)2 in enough water to produce a final solution volume of 259 mL. To
Igoryamba

Answer:

The molar mass of Mg(NO₃)₂, 148.3 g/mol.

Explanation:

Step 1: Given data

  • Mass of Mg(NO₃)₂ (solute): 42.0 g
  • Volume of solution: 259 mL = 0.259 L

Step 2: Calculate the moles of solute

To calculate the moles of solute, we need to know the molar mass of Mg(NO₃)₂, 148.3 g/mol.

42.0 g × 1 mol/148.3 g = 0.283 mol

Step 3: Calculate the molarity of the solution

M = moles of solute / liters of solution

M = 0.283 mol / 0.259 L

M = 1.09 M

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Monochloroacetic acid (HC2H2ClO2) is a skin irritant that is used in "chemical peels" intended to remove the top layer of dead s
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<u>Answer:</u> The pH of the solution is 1.703

<u>Explanation:</u>

We are given:

Concentration of monochloroacetic acid = 0.31 M

The chemical equation for the dissociation of monochloroacetic acid follows:

                  HC_2H_2ClO_2\rightleftharpoons H^++C_2H_2ClO_2^-

<u>Initial:</u>               0.31

<u>At eqllm:</u>        0.31-x             x            x

The expression of K_a for above equation follows:

K_a=\frac{[H^+][C_2H_2ClO_2^-}}{[HC_2H_2ClO_2]}

We are given:

K_a=1.35\times 10^{-3}

Putting values in above equation follows:

1.35\times 10^{-3}=\frac{x\times x}{(0.31-x)}\\\\x=-0.021,0.0198

Neglecting the negative value of 'x' because concentration cannot be negative.

To calculate the pH of the solution, we use the equation:

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