1. What is the difference between charging by conduction and charging by induction?

Use the periodic table to select which type of bond is present and which of the listed properties is most likely for each substa

jenyasd209 [6]

Answer:

A = Metallic Bond

B = Strong bonding, strong conductor, high melting and boiling points

Explanation:

Since the bond is between two metals (located in groups 11 and 12), they would experience metallic bonding. Metallically bonded molecules have high melting and boiling points due to the strength of the metallic bond. They also experience strong electrical current due to the there delocalized electrons.

3 0

3 years ago

Type of change that doesn't involve the formation of new kind of matter

Artyom0805 [142]

A physical change, ie tearing a piece of paper in half.

7 0

3 years ago

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Using the following combustion reaction, describe how it follows the laws of conservation of mass and energy. CH 4 +2O 2 CO 2 +2

AURORKA [14]

Answer:

Explanation:

The law of conservation of mass states that "mass in a system remains constant and that the mass of the product is remains the same as that of the reactants".

Law of conservation of energy states that "energy is neither created nor destroyed in the course of chemical or physical change but can be transformed from one form to another".

Let us properly write the equation:

CH₄ + 2O₂ → CO₂ + 2H₂O

For the conservation of mass:

C has 1mole on both sides

H has 4mole on both sides

O has 4 mole on both sides

For energy, during combustion process, the methane CH₄ burns to liberate heat energy. This is an energy conversion process in which chemical energy in methane releases heat energy.

8 0

3 years ago

What particles are involved in nuclear reactions, but not in chemical reactions?

Kisachek [45]

That would be choice A.

Protons and Neutrons.

6 0

3 years ago

Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 42. g of butane is m

taurus [48]

Answer:

127 grams of carbon dioxide

Explanation:

We need to determine the chemical equation first. Butane has a chemical formula of $C_4H_{10}$ , oxygen is $O_2$ , carbon dioxide is $CO_2$ , and water is $H_2O$ . The reactants are butane and oxygen and the products are carbon dioxide and water. So we write:

$C_4H_{10}+O_2$ ⇒ $CO_2+H_2O$

But remember! We need to balance this. Currently, there are 4 carbon atoms (C), 10 hydrogen atoms (H), and 2 oxygen atoms (O) on the left, while there are 1 carbon atom (C), 2 hydrogen atoms (H), and 3 oxygen atoms (O) on the right. Let's place a coefficient of 4 in front of the carbon dioxide and a coefficient of 5 on the water, so that we have equal numbers of carbon and hydrogen atoms on each side:

$C_4H_{10}+O_2$ ⇒ $4CO_2+5H_2O$

However, we need to ensure that there are equal numbers of O atoms, as well. On the left, we have 2 and on the right we have 13, so let's put a coefficient of 6.5 on the oxygen:

$C_4H_{10}+6.5O_2$ ⇒ $4CO_2+5H_2O$

Finally, multiply everything by 2 to get whole number coefficients:

$2C_4H_{10}+13O_2$ ⇒ $8CO_2+10H_2O$

Ah, now we can actually get to the problem!

We need to determine the limiting reactant, so let's convert the 42 g of butane and 150 g of oxygen into moles of any product, say, carbon dioxide. To convert to moles, we need to find the molar mass of each compound.

The molar mass of butane is 4 * 12.01 + 10 * 1.01 = 58.14 g/mol, while the molar mass of oxygen is 2 * 16 = 32 g/mol. We can now set up the equations:

$42 gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}} *\frac{8molCO_2}{2molC_4H_{10}} =2.8896molCO_2$

$150 gO_2*\frac{1molO_2}{32gO_2} *\frac{8molCO_2}{13molO_2} =2.8846molCO_2$

Clearly, we see that 2.8846 < 2.8896, which means that oxygen is the limiting reactant. In other words, the most products can be made when the oxygen is all used up.

Now let's finally convert moles of carbon dioxide into grams by multiplying by its molar mass, which is 12.01 + 2 * 16 = 44.01 g/mol:

$2.8846molCO_2*\frac{44.01gCO_2}{1molCO_2} =127gCO_2$

Notice that we have 3 significant figures because we had 3 significant figures at the start with 150. grams of oxygen.

<em>~ an aesthetics lover</em>

4 0

3 years ago