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2 years ago

Look at this set of 5 numbers: 21471 By how much would the mode decrease if the number 1 were added to the set?

Mathematics

1 answer:

Fofino [41]2 years ago

6 0

Answer:

Zero

Step-by-step explanation:

The mode is the number of most repeated data in the set.

Given set 2, 1, 4, 7, 1 has mode 1 (repeated twice).

If we add 1 to the set the mode will remain 1 as it will repeat three times, so the mode won't change.

There is no change in mode, so the mode decrease is zero.

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Mrs watson is 28 years older than her daughter sarah's age x mrs watson is less than 54 year old how old is sara

iogann1982 [59]

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4 years ago

Read 2 more answers

What is the factor of x^2 -9x +18

Rashid [163]

X^2 - 9x + 18
factors of 18: 1*18, 2*9, 3*6,
the sums of the factors: 19, 11, 9
the positive 18 tells us both factors have the same sign, the negative 9 tells us they are both negative
(x - 3)(x - 6)

5 0

3 years ago

If D is midpoint of side BC of triangle ABC. P and Q are points lying respectively on side AB and AC such that DP is parallel to

LUCKY_DIMON [66]

See proof below

Step-by-step explanation:

Assume triangle ABC to have vertices at;

A(2,-1), B(2,-7) and C(6,-7)

D is midpoint of BC, thus D is at (4,-7)

The P and Q, are lying on side AB and AC, hence assume P is at (2,-4) and Q is at (4,-4) such at DP is parallel to QA

Plot the points on a graph tool and join the points to view the sketch.

To prove area of triangle CPQ is 1/4 area of ABC will be;

Find area ABC and CPQ then compare the areas.

Apply the distance formula to find the length of sides of the triangles then find the areas.

The distance formula is;

$d=\sqrt{x_2-x_1)^2+(y_2-y_1)^2}$

Length of side AB from the sketch is;

$AB=\sqrt{(2-2)^2+(-7--1)^2} =\sqrt{-6^2} =\sqrt{36} =6units$

Length of side BC will be;

$BC=\sqrt{(-7--7)^2+(6-2)^2} =\sqrt{4^2} =\sqrt{16} =4units$

Thus area of triangle ABC will be;

1/2 *base length*height ------because it is a right-triangle

1/2*4*6=12 square units

Find the lengths of all sides of triangle CPQ

Length of side PQ is half that of side BC thus PQ=2 units

Length of side PC is;

$PC=\sqrt{(6-2)^2+(-7--4)^2} =\sqrt{4^2+-3^2} =\sqrt{16+9} =\sqrt{25} =5units$

Length of side QC will be;

$QC=\sqrt{(6-4)^2+(-7--4)^2} =\sqrt{2^2+-3^3} =\sqrt{4+9} =\sqrt{13}$

QC= √13 = 3.6 units

Find area of triangle CPQ given all sides by applying the Heron's formula for area of triangle which is;

A=√s(s-a)(s-b)(s-c) where;

A=area of the triangle

s= half the perimeter of the triangle

a=side PQ = 2 units

b=side PC = 5 units

c= side QC = 3.6 units

Finding the perimeter of triangle CPQ will be;

P=sum of all sides

P=2+5+3.6 =10.6 units

s=10.6/2 = 5.3

Area of the triangle CPQ will be;

$A=\sqrt{5.3(5.3-2)(5.3-5)(5.3-3.6)} \\A=\sqrt{5.3(3.3)(0.3)(1.7)} \\A=\sqrt{8.9} =2.98$

A=3.0 (1 decimal place)

Compare the areas;

Area of triangle ABC=12 square units

Area of triangle CPQ = 3 square units

Area of triangle CPQ / Area of triangle ABC = 3/12 =1/4

Thus you have proved that area of triangle CPQ is 1/4 th area of triangle ABC because 1/4 *12 =3

Learn More

Area of a triangle ;brainly.com/question/14869984

The Heron's formula : brainly.com/question/10713495

Keywords: midpoint, triangle, sides, parallel, prove , area, equal

#LearnwithBrainly

6 0

3 years ago

PLS HELP!!!!!!!!!!!!!

fgiga [73]

Answer:

7+1- -7

Step-by-step explanation:

i just guessed :)

3 0

3 years ago

20 POINTS PLEASE NEED HELP! PICTURE IS SHOWN!

Rus_ich [418]

it's quite simple. all you need too do is add the total amount then divide

group A (box one) =(0.85). Group A (directly under the first one) =(0.15). Group B do 34 + 14 to get 48 then you divide 34÷48 to get (0.71) that is your answer to the first box in Group B then you do the exact same thing as you did in the first one, but swich 14 for 34 and you will get (0.29)

Simplified to make it easier to read.

Group 1. (0.85 0.71)

Group 2. (0.15 0.29)

Can you mark me Branliest. plz

7 0

3 years ago