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ElenaW [278]
3 years ago
12

Tell whether the sequence is arithmetic. If it is, identify the common difference and write the explicit formula. Please show de

tailed steps: 2, -1, 5,-4,......
Mathematics
1 answer:
NISA [10]3 years ago
5 0

Answer: The sequence is not Arithmetic.

Step-by-step explanation:

It is important to remember that,  by definition, a sequence is Arithmetic when the difference between each term is constant (this difference is called the "Common difference" as it is represented with "d")

Knowing this and given the following sequence provided in the exercise:

2, -1, 5,-4,...

You need to find the differences of the consecutive terms. You get that:

-1-2=-3\\\\5-(-1)=6\\\\-4-5=-9

Therefore, since the differences between the consecutive terms is not constant, you can conclude that the given sequence is not Arithmetic.

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What is the percent of change if 38 is decreased to 25? round to the nearest whole number
motikmotik

Answer:

7.89474% decrease

Step-by-step explanation:

Solution:

Calculate percentage change

from V1 = 38 to V2 = 35

(V2−V1)|V1|×100

=(35−38)|38|×100

=−338×100

=−0.0789474×100

=−7.89474%change

=7.89474%decrease

7 0
2 years ago
Please answer very confuse english very bad que?
nata0808 [166]

Answer:

for the first question, it's (2,2) and for the last question it's (0,2)

4 0
3 years ago
Please Explain/Show your work!
Zigmanuir [339]

Answer:

They are both proportional.

Tank A = .00375 minutes/gallon

Tank B = 2/600 or ~0.003 minutes/gallon

Step-by-step explanation:

They are both proportional because as time increases, the amount of gallons increases.

Tank A unit rate

Tank B unit rate

Rate = rise / run

Choose points on the graph that has definite points.

Tank A = (1.5 mins - 0.75 mins) / 200 gallons

Tank A = .00375 minutes/gallon

Tank B = (2 mins - 0 mins) / 600 gallons

Tank B = 2/600 or .003 minutes/gallon

3 0
3 years ago
Solve the given initial-value problem. <br> (2y + 2t − 3) dt + (8y + 2t − 1) dy = 0, y(−1) = 2.
katrin2010 [14]

Answer:

holy ish  ive never seen anything like this in my life

Step-by-step explanation:

7 0
3 years ago
Time spent using​ e-mail per session is normally​ distributed, with mu equals 11 minutes and sigma equals 3 minutes. Assume that
liq [111]

Answer:

a) 0.259

b) 0.297

c) 0.497

Step-by-step explanation:

To solve this problem, it is important to know the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 11, \sigma = 3

a. If you select a random sample of 25 ​sessions, what is the probability that the sample mean is between 10.8 and 11.2 ​minutes?

Here we have that n = 25, s = \frac{3}{\sqrt{25}} = 0.6

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{11.2 - 11}{0.6}

Z = 0.33

Z = 0.33 has a pvalue of 0.6293.

X = 10.8

Z = \frac{X - \mu}{s}

Z = \frac{10.8 - 11}{0.6}

Z = -0.33

Z = -0.33 has a pvalue of 0.3707.

0.6293 - 0.3707 = 0.2586

0.259 probability, rounded to three decimal places.

b. If you select a random sample of 25 ​sessions, what is the probability that the sample mean is between 10.5 and 11 ​minutes?

Subtraction of the pvalue of Z when X = 11 subtracted by the pvalue of Z when X = 10.5. So

X = 11

Z = \frac{X - \mu}{s}

Z = \frac{11 - 11}{0.6}

Z = 0

Z = 0 has a pvalue of 0.5.

X = 10.5

Z = \frac{X - \mu}{s}

Z = \frac{10.5 - 11}{0.6}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033.

0.5 - 0.2033 = 0.2967

0.297, rounded to three decimal places.

c. If you select a random sample of 100 ​sessions, what is the probability that the sample mean is between 10.8 and 11.2 ​minutes?

Here we have that n = 100, s = \frac{3}{\sqrt{100}} = 0.3

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{11.2 - 11}{0.3}

Z = 0.67

Z = 0.67 has a pvalue of 0.7486.

X = 10.8

Z = \frac{X - \mu}{s}

Z = \frac{10.8 - 11}{0.3}

Z = -0.67

Z = -0.67 has a pvalue of 0.2514.

0.7486 - 0.2514 = 0.4972

0.497, rounded to three decimal places.

5 0
3 years ago
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