Make an x and y table, and pick any values to plug in for x in the equation.
I will use the numbers from -2 to 2
Now plug in the values you picked for x into the equation to find its y-value
x = -2
y = 3x - 1 Plug in -2 for x
y = 3(-2) - 1
y = -6 - 1
y = -7
x = -1
y = 3x - 1
y = 3(-1) - 1
y = -3 - 1
y = -4
Do the same for the rest of the numbers, and graph each point and draw a line connecting them.
The area is 192 cm^2
the sides are 20 20 24 with the base being 24
to figure out the height you have to use Pythagorean theorem of the triangle cut in half so 12^2 + b^2 = 20^2
b= 16 = height
b*h* .5= area 16* 24* .5= 192
Answer:
Step-by-step explanation:
Let's FOIL this out and get it into standard quadratic format:
. The lack of a linear term in the middle means therewas no upwards velocity, consistent with the object being dropped straight down as opposed to thrown up in the air tand then falling in a parabolic path. The -4.9t² represents the acceleration due to gravity, and the 490 represents the height from which the object was dropped. The constant in a quadratic that is modeling parabolic motion always represents the height from which the object was dropped (or launched). That's how you know.
The third one is the answer for this question
Answer:
The given system has NO SOLUTION.
Step-by-step explanation:
Here, the given system of equation is:
6 x - 2 y = 5 .......... (1)
3 x - y = 10 .... (2)
Multiply equation 2 with (-2), we get:
3 x - y = 10 ( x -2)
⇒ - 6 x + 2 y = - 20
Now, ADD this to equation (1) , we get:
6 x - 2 y - 6 x + 2 y = 5 - 20
or, 0 = - 15
WHICH IS NOT POSSIBLE as 0 ≠ -15
Hence, the given system has NO SOLUTION.
