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2 years ago

A 197 g object apparently loses 34 g when fully submerged in a liquid of density 2.3 g/cm3. What is the density of the object

Physics

1 answer:

sergeinik [125]2 years ago

6 0

Answer:

13.33 gm/cm^3

Explanation:

Displacement of liquid =

34 gm / 2.3 gm/cm^3 = 14.783 cm^3

so the VOLUME of the object is 14.783 cm^3

density = 197 gm / 14.783 cm^3 = 13.33 gm/cm^3

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An object has 16 N of force being applied to the right, 16 N of force being applied to the left, and 6 N of force being applied

umka2103 [35]

Answer:

the net force on the object is 6 N.

Explanation:

Given;

force applied to the right on the object, $F_r$ = 16 N

force applied to the left of the object, $F_l$ = 16 N

force applied downward on the object, $F_d$ = 6 N

The net horizontal force on the object = $F_r - F_l = 16N -16N = 0$

The net vertical force on the object = $6 \ N \ downward$

The net force on the object is calculated as;

$F_{net}^2 = 6^2 + 0\\\\F_{net}^2 = 36\\\\F_{net} = \sqrt{36} \\\\F_{net} = 6 \ N$

Therefore, the net force on the object is 6 N.

7 0

3 years ago

A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 2.3 cm from the axis of rotation. (a) Calcul

VLD [36.1K]

Answer:

a) $a_{r} = 0.275\,\frac{m}{s^{2}}$ , b) $\mu_{s} = 0.028$ , c) $\mu_{s} = 0.036$

Explanation:

a) The linear acceleration of the watermelon seed is:

$a_{r} = \omega^{2}\cdot r$

$a_{r} = \left[\left(33\,\frac{rev}{min} \right)\cdot \left(2\pi\,\frac{rad}{rev} \right)\cdot \left(\frac{1}{60}\,\frac{min}{s} \right)\right]^{2}\cdot (0.023\,m)$

$a_{r} = 0.275\,\frac{m}{s^{2}}$

b) The watermelon seed is experimenting a centrifugal acceleration. The coefficient of static friction between the seed and the turntable is calculated by the Newton's Laws:

$\Sigma F = \mu_{s}\cdot m\cdot g = m\cdot a$

$a = \mu_{s}\cdot g$

$\mu_{s} = \frac{a}{g}$

$\mu_{s} = \frac{0.275\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }$

$\mu_{s} = 0.028$

c) Angular acceleration experimented by the turntable is:

$\alpha = \frac{\omega-\omega_{o}}{\Delta t}$

$\alpha = \frac{3.456\,\frac{rad}{s}-0\,\frac{rad}{s} }{0.36\,s}$

$\alpha = 9.6\,\frac{rad}{s^{2}}$

The tangential acceleration experimented by the watermelon seed is:

$a_{t} = \left(9.6\,\frac{rad}{s^{2}} \right)\cdot (0.023\,m)$

$a_{t} = 0.221\,\frac{m}{s^{2}}$

The linear acceleration experimented by the watermelon seed is:

$a = \sqrt{a_{t}^{2}+a_{r}^{2}}$

$a = \sqrt{\left(0.221\,\frac{m}{s^{2}} \right)^{2}+\left(0.275\,\frac{m}{s^{2}} \right)^{2}}$

$a = 0.353\,\frac{m}{s^{2}}$

The minimum coefficient of static friction is:

$\mu_{s} = \frac{0.353\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }$

$\mu_{s} = 0.036$

4 0

3 years ago

What would happen if a bird was a vulture riding on a zebra's back? How would it affect the relationship?

OLEGan [10]

The zebra could be "hen pecked" if the vulture was a hen bird. On the other hand, the two might get along ok. In UK, it they 'd make a useful combination helping each other to cross increasingly dangerous roads (joke).

6 0

4 years ago

Help please, I don't get it

Sergio [31]

Answers:

a) $\hat F=(0.83,-0.55) N$

b) $\hat D=(-0.44,-0.89) m$

c) $\hat V=(-0.47,0.88) m/s$

Explanation:

A unit vector is a vector whose magnitude (length) is equal to 1. This kind of vector is identified as $\hat v$ and the way to calculate is as follows: