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3 years ago

All moving objects don’t have momentum A. True B. False

Physics

2 answers:

mestny [16]3 years ago

4 0

Answer:

Explanation:

Some objects gain momentum.

GREYUIT [131]3 years ago

4 0

All moving objects have momentum.
We know, momentum = mass × velocity
So, when an object is moving, it has velocity.
So, there is momentum.

Answer:

B. False

Hope you could understand.

If you have any query, feel free to ask.

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In a thermally isolated environment, you add ice at 0°C and steam at 100°C. (a) Determine the amount of steam condensed (in g) a

kondor19780726 [428]

Answer:

a) 11.2 g

b) 3.73 g.

Explanation:

a) If we assume temperature of mixture to be 100°C , heat released by steam will be 11.2 x 540 = 6048 cals and heat gain gained by will be

79 x 80 + 79 x 1 x 100 = 14220 cals . Since former heat is less than later heat ,water will not be warmed up to 100°C. Let equilibrium temperature be t .

Heat gained by water = 79 x 80 + 79 x 1 x t = 11.2 x 540 + 11.2( 100 - t )

t = 9.4°

amount of steam condensed = 11.2 g.

b) In this case, whole of water will be warmed up to 100°C as steam is much .heat required by water to warm up to boiling point

= 11.2 x 80 + 11.2 x 100 = 2016 cals

amount of steam condensed = 2016 / 540 = 3.73 g .

3 0

3 years ago

2. An athlete of average size is hanging from the end of a 20 m long rope, which has a mass of 4 kg and is attached to a hook in

a_sh-v [17]

Answer:

t = 0.319 s

Explanation:

With the sudden movement of the athlete a pulse is formed that takes time to move along the rope, the speed of the rope is given by

v = √T/λ

Linear density is

λ = m / L

λ = 4/20

λ = 0.2 kg / m

The tension in the rope is equal to the athlete's weight, suppose it has a mass of m = 80 kg

T = W = mg

T = 80 9.8

T = 784 N

The pulse rate is

v = √(784 / 0.2)

v = 62.6 m / s

The time it takes to reach the hook can be searched with kinematics

v = x / t

t = x / v

t = 20 / 62.6

t = 0.319 s

7 0

3 years ago

How fast must a 1000 kg car be moving to have a kinetic energy of:

VMariaS [17]

Answer:

$\mathrm{(a)}\: 2\: \mathrm{m/s}\\\mathrm{(b)}\: 20\: \mathrm{m/s}\\$

Explanation:

The kinetic energy of an object is given by $KE=\frac{1}{2}mv^2$ where $m$ is the mass of the object and $v$ is the velocity of the object.

We can set up the following equations with the information given:

$\mathrm{(a)}\: 2.0\cdot 10^3=\frac{1}{2}\cdot 1000\cdot v^2, \\v=\fbox{$2\: \mathrm{m/s}$}$

For part B, we have the same equation, but kinetic energy is now $2.0\cdot 10^5$ .

Therefore:

$\mathrm{(b)}\: 2.0\cdot 10^5=\frac{1}{2}\cdot 1000\cdot v^2, \\v=\fbox{$20\: \mathrm{m/s}$}$ .

6 0

3 years ago

You apply the same force to two objects. Object 1 has mass M and object 2 has mass 5M. The acceleration of object 2 is

Hitman42 [59]

five times that of object l

3 0

3 years ago

A 4.00 µf capacitor is connected to a 12.0 v battery.

atroni [7]

(a) The capacitance of the capacitor is:
$C=4 \mu F=4 \cdot 10^{-6}F$
and the voltage applied across its plates is
$V=12.0 V$

The relationship between the charge Q on each plate of the capacitor, the capacitance and the voltage is:
$C= \frac{Q}{V}$
and re-arranging it we find the charge stored in the capacitor:
$Q=CV=(4 \cdot 10^{-6} F)(12.0 V)=4.8 \cdot 10^{-5} C$

(b) The electrical potential energy stored in a capacitor is given by
$U= \frac{1}{2}CV^2$
where C is the capacitance and V is the voltage. The new voltage is
$V=1.50 V$
so the energy stored in the capacitor is
$U= \frac{1}{2}(4 \cdot 10^{-6} F)(1.50 V)^2=4.5 \cdot 10^{-6} J$

3 0

3 years ago

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