Question

An object has 16 N of force being applied to the right, 16 N of force being applied to the left, and 6 N of force being applied downward. What is the net force on the object?

Answer 1

Answer:

the net force on the object is 6 N.

Explanation:

Given;

force applied to the right on the object, $F_r$ = 16 N

force applied to the left of the object, $F_l$ = 16 N

force applied downward on the object, $F_d$ = 6 N

The net horizontal force on the object = $F_r - F_l = 16N -16N = 0$

The net vertical force on the object = $6 \ N \ downward$

The net force on the object is calculated as;

$F_{net}^2 = 6^2 + 0\\\\F_{net}^2 = 36\\\\F_{net} = \sqrt{36} \\\\F_{net} = 6 \ N$

Therefore, the net force on the object is 6 N.