1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleks [24]
3 years ago
10

An object has 16 N of force being applied to the right, 16 N of force being applied to the left, and 6 N of force being applied

downward. What is the net force on the object?
Physics
1 answer:
umka2103 [35]3 years ago
7 0

Answer:

the net force on the object is 6 N.

Explanation:

Given;

force applied to the right on the object, F_r = 16 N

force applied to the left of the object, F_l = 16 N

force applied downward on the object, F_d = 6 N

The net horizontal force on the object = F_r - F_l = 16N -16N = 0

The net vertical force on the object = 6 \ N \ downward

The net force on the object is calculated as;

F_{net}^2 = 6^2 + 0\\\\F_{net}^2 = 36\\\\F_{net} = \sqrt{36} \\\\F_{net} = 6 \ N

Therefore, the net force on the object is 6 N.

You might be interested in
5) A 20.0 kg cart with no friction wheels sits on a table. A light string is attached to it and runs over a low friction pulley
ella [17]

Answer:

1) Please find attached, created with Microsoft Visio

2) The acceleration of the masses connected by the light string is 0.00735 m/s²

3) The tension in the cord is 0.147 N

4) The time it would take the block to go 1.2 m to the edge of the table is approximately 18.07 s

5) The velocity of the cart as soon as it gets to the edge of the table is 0.042 m/s

Explanation:

1) Please find attached, the required free body diagram, showing the tension, weight and frictional (zero friction) forces acting on the cart and the mass created with Microsoft Visio

2) The acceleration of the masses connected by the light string is given as follows;

F = Mass, m × Acceleration, a

The mass of the truck, M = 20.0 kg

The mass attached to the string, hanging rom the pulley, m = 0.0150 kg

The force, F acting on the system = The pulling force on the cart = The tension on the cable = The weight of the hanging mass = 0.0150 × 9.8 = 0.147 N

The pulling force acting on the cart, F = M × a

∴ F = 0.147 N = 20.0 kg × a

a = 0.147 N/(20.0 kg) = 0.00735 m/s²

The acceleration of the truck = a = 0.00735 m/s²

3) The tension in the cord = F = 0.147 N

4) The time, t, it would take the block to go 1.2 m to the edge of the table is given by the kinematic equation, s = u·t + 1/2·a·t²

Where;

s = The distance to the edge of the table = 1.2 m

u = The initial velocity = 0 m/s (The cart is assumed to be initially at rest)

a = The acceleration of the cart = 0.00735 m/s²

t = The time taken

Substituting the known values, gives;

s = u·t + 1/2·a·t²

1.2 = 0 × t + 1/2 ×0.00735 × t²

1.2 = 1/2 ×0.00735 × t²

t² = 1.2/(1/2 ×0.00735) ≈ 326.5306

t = √(1.2/(1/2 ×0.00735)) ≈ 18.07

The time it would take the block to go 1.2 m to the edge of the table = t ≈ 18.07 s

5) The velocity, v, of the cart as soon as it gets to the edge of the table is given by the kinematic equation, v² = u² + 2·a·s as follows;

v² = u² + 2·a·s

u = 0 m/s

v² = 0² + 2 × 0.00735 × 1.2 = 0.001764

v = √(0.001764) = 0.042

The velocity of the cart as soon as it gets to the edge of the table = v = 0.042 m/s.

7 0
3 years ago
Read 2 more answers
Compare and contarst the difference between saturated and unsaturated solutions and supersaturated
JulsSmile [24]

Answer:

Unsaturated Solution: Less amount of salt in water, clear solution, no precipitation. Saturated Solution: The maximum amount of salt is dissolved in water, Colour of the solution slightly changes, but no precipitation. Supersaturated Solution: More salt is dissolved in water, Cloudy solution, precipitation is visible

6 0
2 years ago
Draw the vector C⃗ =A⃗ +2B⃗ .
spin [16.1K]

Answer:

A) C is 2 units towards right

B) C is 9 units towards right and 3 units towards up

C) C is 4 units towards right and 1 unit towards down

Explanation:

Drawings are given in the attachment.

A)Since,

A is 4 units towards right,

B is 1 unit towards left,

Then,

C is 2 units towards right.

B) Since,

A is 4 units towards right and 2 units towards up,

B is 1 unit towards left,

Then,

C is 9 units towards right and 3 units towards up.

C) Since,

A is 4 units towards right and 2 units towards up,

B is 1 unit towards right, and 1 unit towards down

Then,

C is 4 units towards right and 1 unit towards down.

4 0
4 years ago
Anna is conducting an experiment to determine how weather affects cell phone reception. She is trying to decide the best way to
aev [14]

Answer:

D. Test a cell phone's reception in the exact same location under various atmospheric conditions

Explanation:

Components of an experiment:

Independent variable:

A manipulated variable, in an experiment or study, whose presence or degree incurs a change in the  dependent variable.

Dependent variable:

A variable which is being studied in the experiment and is supposed to change with respect to the independent variable.

Control variable:

Control variable includes the variables which are of no concern in the experiment and must be constant so that they do not interfere with the results of the experiment. Change in control variable might affect the results of an experiment.

In Anna's experiment, the independent variable is the atmospheric conditions. The dependent variable is cell phone reception that will change according to the atmospheric conditions. All other things related to the experiment are control variables like cellphone, location of the cell phone. Both of these must stay constant to collect the best data.

Hence, the best option is D.

4 0
4 years ago
A plane is flying due west at 34 m/s. It encounters a wind blowing at 19 m/s south. Find the resultant veloci
Drupady [299]

Answer:

<em>The resultant velocity has a magnitude of 38.95 m/s</em>

Explanation:

<u>Vector Addition</u>

Given two vectors defined as:

\vec v_1=(x_1,y_1)

\vec v_2=(x_2,y_2)

The sum of the vectors is:

\vec v=(x_1+x_2,y_1+y_2)

The magnitude of a vector can be calculated by

d=\sqrt{x^2+y^2}

Where x and y are the rectangular components of the vector.

We have a plane flying due west at 34 m/s. Its velocity vector is:

\vec v_1=(-34,0)

The wind blows at 19 m/s south, thus:

\vec v_2=(0,-19)

The sum of both velocities gives the resultant velocity:

\vec v =(-34,-19)

The magnitude of this velocity is:

d=\sqrt{(-34)^2+(-19)^2}

d=\sqrt{1156+361}=\sqrt{1517}

d = 38.95 m/s

The resultant velocity has a magnitude of 38.95 m/s

3 0
3 years ago
Other questions:
  • A car traveling 75km/h slows down at a constant 0.50m/s^2 just by letting up the gass. a: calculate the distance the car coasts
    15·1 answer
  • In a parallel circuit, if bulb #2 were to blow out, bulb #1 would stay lit or go out?
    5·1 answer
  • The result of changing a physical sound wave into an analogous electrical signal using a transducer (such as a microphone) is ca
    14·1 answer
  • Which statement accurately describes the interaction between the poles of two bar magnets
    14·2 answers
  • If the net force on an object is zero then the object has
    8·1 answer
  • Which is more dangerous to living things, gamma rays or X-rays? Explain.
    13·1 answer
  • How are atoms related to elements?
    9·1 answer
  • A box with a mass of 15.0 kg is being pushed on a level surface with a
    11·1 answer
  • Why is a star an example of a good blackbody radiator?
    5·1 answer
  • Which is an example of a trace fossil?
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!