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mart [117]
2 years ago
11

4.0 J of work are performed in stretching a spring with a spring constant of 2500 N/m. How much is the spring stretched?

Physics
1 answer:
earnstyle [38]2 years ago
3 0

energy = elastic \: potential

4 =  \frac{1}{2} kx {}^{2}

4 =  \frac{1}{2} (2500)x {}^{2}

4 = 1250x {}^{2}

x {}^{2}  =  \frac{4}{1250}  = 0.0032 \: meters

x =  \sqrt{0.0032}  = 0.05657 \: meters

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