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enyata [817]
4 years ago
12

Determine which heat transfers below are due to the process of conduction. I) You walk barefoot on the hot street and it burns y

our toes. II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned. III) A flame heats the air inside a hot air balloon and the balloon rises. IV) A boy sits to the side of a campfire. He is 10 feet away, but still feels warm.
Physics
1 answer:
Taya2010 [7]4 years ago
3 0

Answer:

I) You walk barefoot on the hot street and it burns your toes.

II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned.

Explanation:

In conduction mode of heat transfer we know that the energy is transferred from one system to other system due to direct contact of two bodies

Here due to this direct contact the energy is transferred via a given solid or liquid medium

In this type of heat transfer medium particles will remain in its own position only the energy is transferred.

So here we can say the correct answer will be

I) You walk barefoot on the hot street and it burns your toes.

II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned.

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Suppose that she pushes on the sphere tangent to its surface with a steady force of F = 75 N and that the pressured water provid
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Answer:

The time taken to rotate the sphere one time is,  t = 22 s

Explanation:

Given data,

The mass of the sphere, m = 8200 kg

The radius of the sphere, r = 90 cm

                                             = .9 m

The force applied by the girl, F = 75 N

The moment of inertia of the sphere is,

                            I = 2/5 mr²

                              = (2/5) 8200 x (.9)²

                              = 2657 kg·m²

The torque,

                            τ = I α

                             75 x 0.9 = 2657 x α

                              α = 0.0254 rad/s²

The angular displacement,

                            θ = ½αt²

                             2π =  ½ x 0.0254 rad/s² x t²

                                t = 22 s

Hence, the time taken to rotate the sphere one time is,  t = 22 s

8 0
3 years ago
Calculate the average speed of the moon around the earth. The moon has a period of revolution of 27.3 days and an average distan
klio [65]
<h2>The average speed of the moon around the earth is 1021.74 m/s</h2>

Explanation:

Radius of moon around earth, r = 3.84 × 10⁸ m

Circumference of orbit = 2πr = 2 x 3.14 x 3.84 × 10⁸

Circumference of orbit = 2.41 x 10⁹ m

Time taken, t = 27.3 days = 27.3 x 24 x 60 x 60 = 2358720 seconds

We have

       Circumference of orbit = Speed of moon x Time taken

        2.41 x 10⁹ = Speed of moon x 2358720

       Speed of moon = 1021.74 m/s

The average speed of the moon around the earth is 1021.74 m/s

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3 years ago
Calculate the kinetic energy of a 2kg ball moving at 5m/s
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Answer:

25

Explanation:

The kinetic energy is 25

8 0
3 years ago
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
zhuklara [117]

Complete Question

You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headlights that are 0.681 m apart. At what distance, in kilometres, are you marginally able to discern that there are two headlights rather than a single light source?Take the wavelength of the light to be 549 nm and your pupil diameter as 4.63 mm.  

Answer:

The distance is  z  = 4707.6 \ m

Explanation:

From the question we are told that

    The is distance between the headlight is d = 0.681 \ m

   The wavelength is  \lambda = 549 \ nm = 549 *10^{-9} \ m

    The  pupil diameter is  D  = 4.63 \ mm = 0.00463 \ m

Generally, we can mathematically evaluate the resolution of the eye as

            \theta  = \frac{1.22 *  \lambda }{D}

    substituting values

              \theta  = \frac{1.22 *  549 *10^{-9} }{0.00463}

              \theta  =  (1.45 *10^{-4} )^o

Now according to SOHCAHTOA rule  

         sin \theta  =  \frac{ d}{z}

Where z is  the distance at which the eye can discern the two head light

  given that the angle is very small sin \theta =  \theta

=>    \theta  =  \frac{ d}{z}

substituting values

     1.45*10^{-4}  =  \frac{ 0.681}{z}

=>   z  = \frac{0.681}{1.45 *10^{-4}}

=>    z  = 4707.6 \ m

   

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