Answer:
By order of increasing magnitude:
D. Make sure the USB device is plugged in properly.
A. Try a different USB cable.
B. Replace the USB device.
C. Install a new USB controller card.
Explanation:
Start with whatever is simplest first. Most errors are simply ID-10-T mistakes.
Answer:
b. instantiated.
Explanation:
In computer programming, to be instatiated or when variables are instatiated; this simply refers to the acts of making example out of a group variables or a form of template. For example in a situation of class of objects.
Hence, in this case, the correct answer to the question above is the option B, in which Variables set equal to patterns are said to be INSTATIATED
Digital data<span>. Biometric </span>data<span>. Digital </span><span>data</span>
Answer:
The probability that among three randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot is 0.964
If the survey subjects <em>volunteered</em> to respond , then those with the strongest opinions are most likely respond. The survey sample is then not randomly selected, the survey may have a <em>response bias.</em>
Explanation:
Let P(at least one is more careful about personal information when using a public Wi-Fi hotspot) denote the probability that among three randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot, then we have the equation
P(at least one is more careful about personal information when using a public Wi-Fi hotspot) = 1 - P(none of the selected users is more careful about personal information when using a public Wi-Fi hotspot)
- If 67% of Internet users are more careful about personal information when using a public Wi-Fi, then 33% of them are not.
P(none of the selected users is more careful about personal information when using a public Wi-Fi hotspot) =
≈ 0.036
P(at least one is more careful about personal information when using a public Wi-Fi hotspot) = 1 - 0.036 = 0.964
Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

⇒ t = 8.7*10⁻⁴ sec.