Question

At what temperature teq do the forward and reverse corrosion reactions occur in equilibrium?

Answer 1

Standard Gibb's free energy at 298K and 5975K is 3.16×10⁶J and -3.83×10⁵J respectively, and temperature at equilibrium state is 5362.3 K.

What is the standard Gibb's free energy?

The complete question is in the brainly link at the end. We can say that;

Standard Gibb's free energy of any reaction is gotten from the formula;

∆G° = ∆H° - T∆S°

where;

∆G° is change in free energy

∆H° is change in enthalpy = 3352 kJ = 3352 × 10³J

∆S° is change in entropy = 625.1 J/K

T is absolute temperature = 298 K

Plugging in the relevant values into the gibbs energy equation gives;

∆G° = (3352 × 10³) - (298 × 625.1)

∆G° = 3.16 × 10⁶J

Gibb's free energy at temperature of 5,975 K is;

∆G° = (3,352 × 10³) - (5,975 × 625.1)

∆G° = -3.83 × 10⁵J

At the equilibrium state, the value of Gibb's free energy is zero. Thus we can calculate the temperature as;

0 = (3352 × 10³)J - (T × 625.1 J/K)

Solving for T gives;

T = 5362.3 K

Read more about Standard gibbs free energy at; brainly.com/question/17205875