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den301095 [7]
3 years ago
10

The teachers had to transport 166 students by bus on a field trip. Each bus holds 65 students. How many buses do they need to or

der so no one is left behind?
Mathematics
2 answers:
Oksanka [162]3 years ago
7 0
In order for no one to be left behind you would need 3 buses because you cant have 2.5 buses.
Hope that answers your question
Aleksandr-060686 [28]3 years ago
3 0
3 busses are needed for all of the kids
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5x+9=2x+7+3x-15
andrew11 [14]

Answer:

No Solutions

Step-by-step explanation:

Step 1:

5x + 9 = 2x + 7 + 3x - 15  Equation

Step 2:

5x + 9 = 5x - 8   Add and Subtract

Step 3:

9 = - 8    Subtract 5x on both sides

Answer:

9 ≠ - 8       9 cannot equal - 8

Hope This Helps :)

3 0
3 years ago
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An expression is shown 342 / 8 What is the quotient expressed as a fraction?
tekilochka [14]
/ also means division so the answer is 42.75
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4 years ago
A glass box shaped like a rectangular prism has width 7 inches, length 9 inches, and height 12 inches. It is being shipped in a
Nadusha1986 [10]

Answer:

744 in³

Step-by-step explanation:

Since you are filling the larger box with both rectangular prism and Styrofoam peanuts, you need to find the overall volume of the larger box and subtract the volume of the glass box to find the amount of space that the Styrofoam peanuts need to take up.  

Volume (prism) = Bh, where B = area of the base, h = height

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8 0
3 years ago
From a group of 3 men and 4 women, a delegation of 2 is selected. What is the expected number of men in the delegation?
Ostrovityanka [42]

Answer:

The expected number of men in the delegation is 0.86.

Step-by-step explanation:

Number of men = 3

Number of women = 4

A delegation of 2 is selected.

Let X be the number of men selected. So, the possible values of X are 0,1,2.

P(X=0)=\dfrac{^3C_0\times ^4C_2}{^7C_2}=\dfrac{2}{7}

P(X=1)=\dfrac{^3C_1\times ^4C_1}{^7C_2}=\dfrac{4}{7}

P(X=2)=\dfrac{^3C_2\times ^4C_0}{^7C_2}=\dfrac{1}{7}

The expected number of men in the delegation is

E(x)=0\times P(X=0)+1\times P(X=1)+2\times P(X=2)

E(x)=0\times \dfrac{2}{7}+1\times \dfrac{4}{7}+2\times \dfrac{1}{7}

E(x)=\dfrac{6}{7}

E(x)\approx 0.86

Therefore, the expected number of men in the delegation is 0.86.

4 0
3 years ago
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