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Marrrta [24]
3 years ago
9

One common factor of two numbers is 40. Another common factor is 10. If both numbers are less than 100, what are the two numbers

?
Mathematics
1 answer:
lina2011 [118]3 years ago
3 0
If 40 can be an answer, I would say 40 and 80. Both use 40 and 10 as a GCF.
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2a - 4b +3ab -5a +2b
DaniilM [7]

Answer:

-3a-2b+3ab

Step-by-step explanation:

2a-5a

-4b+2b

6 0
3 years ago
Read 2 more answers
Findℒ{f(t)}by first using a trigonometric identity. (Write your answer as a function of s.)f(t) = 12 cost −π6
allsm [11]

Answer:

L(f(t)) = \dfrac{6}{S^2+1} [\sqrt{3} \ S +1 ]

Step-by-step explanation:

Given that:

f(t)  = 12 cos (t- \dfrac{\pi}{6})

recall that:

cos (A-B) = cos AcosB + sin A sin B

∴

f(t) = 12 [cos\  t \  cos \dfrac{\pi}{6}+ sin \ t  \ sin \dfrac{\pi}{6}]

f(t) = 12 [cos \  t \ \dfrac{3}{2}+ sin  \ t  \ sin \dfrac{1}{2}]

f(t) = 6 \sqrt{3} \ cos \ (t) + 6 \ sin \ (t)

L(f(t)) = L ( 6 \sqrt{3} \ cos \ (t) + 6 \ sin \ (t) ]

L(f(t)) = 6 \sqrt{3} \ L [cos \ (t) ] + 6\ L [ sin \ (t) ]

L(f(t)) = 6 \sqrt{3}  \dfrac{S}{S^2 + 1^2}+ 6 \dfrac{1}{S^2 +1^2}

L(f(t)) = \dfrac{6 \sqrt{3} +6 }{S^2+1}

L(f(t)) = \dfrac{6( \sqrt{3} \ S +1 }{S^2+1}

L(f(t)) = \dfrac{6}{S^2+1} [\sqrt{3} \ S +1 ]

7 0
2 years ago
Jane owns 60% of the private catering corporation there are 1200 shares in the entire corporation how many shares does Jane own
IrinaVladis [17]
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4 0
3 years ago
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PilotLPTM [1.2K]

Answer:

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Step-by-step explanation:

x²+8x+12

(x+6)(x+2)

So x+6 and x+2 are factors of x²+8x+12

5 0
2 years ago
What is 696 divided by 12 and show your work please
Vinil7 [7]

Answer:

696/12

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Step-by-step explanation:

The answer is 58 mark me brainliest

4 0
2 years ago
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