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irga5000 [103]
3 years ago
14

Find the area of the irregular figure

Mathematics
2 answers:
lukranit [14]3 years ago
7 0
Rectangle=21 times 14=294 cm^2
Triangle=Base Times Height 
Height=21-12=9cm
Area of triangle=16 times 9 =144

Area of both=294+144=438cm^2

sdas [7]3 years ago
4 0

Answer:

The area of the irregular figure is 366\ cm^{2}

Step-by-step explanation:

we know that

The area of the irregular figure is equal to the area of rectangle plus the area of triangle

The area of rectangle is equal to

A=14*21=294\ cm^{2}

The area of triangle is equal to

A=\frac{1}{2}(16)(21-12)=72\ cm^{2}

Sum the areas

294\ cm^{2}+72\ cm^{2}=366\ cm^{2}

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Step-by-step explanation:

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8 0
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Question 20 fast please
kipiarov [429]

Answer:

Square root of 4 is 2

so  1+\frac{[1+\sqrt{2x-1]}^2 }{4}=4

frac{[1+sqrt{2x-1]}^2 }{4}=3

so 1+sqrt{2x-1]}^2=12

so 1+sqrt{2x-1}=V12

sqrt{2x-1}=V12-1

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I put an attachment to explain better

   

Step-by-step explanation:

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