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fgiga [73]
2 years ago
8

Three gene loci, A, B, and D assort independently, and alleles A, B and D are dominant over alleles a, b, and d. What is the pro

bability of an ABd gamete from an AABbDd individual
Biology
1 answer:
frosja888 [35]2 years ago
6 0

Following the product probability rule and assuming independence among genes, the probability of an ABd gamete from an AABbDd individual is 1/4.

<h3>What does the product probability rule state?</h3>

The product probability rule allows us to calcuate the probability of occurrence of two or more events at the same time. It is about a joint probability of two or more events that might happen simultaneously, not excluding each other.

This rule is based on the dependence or independence of the events. Two events, A and B, are independent of each other if one of them does not affect the occurrence of the other one.

The rule establishes that the occurrence probability of two independent events -A and B- together is the multiplication product of the probability of occurring A by the probability of occurring B.

P(A∩B) = P(A) x P(B)

<u>Available data</u>:

  • A, B, C alleles are dominant over a, b, and c alleles
  • These genes assort independently
  • Individual AABbDd

Each gamete will receive one of the alleles of each gene.

AA ⇒ Gametes can receive only A allele 2/2 A

Bb ⇒ Gametes can receive either B or b alleles ⇒ 1/2 B and 1/2 b

Dd ⇒ Gametes can receive either D or d alleles ⇒ 1/2 D and 1/2 d

The  occurrence probability of ABd is

P(ABd) = P(A) x P(B) x P(d) = 2/2 x1/2 x 1/2 = 2/8 = 1/4.

The probability of an ABd gamete from an AABbDd individual is<u> 1/4. </u>

You will learn more about probability rule at

brainly.com/question/14399918

brainly.com/question/797141

brainly.com/question/333419

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