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Natali [406]
2 years ago
5

A 5.5 × 10–3 M solution of fluoroacetic acid, CH2FCOOH, has a pH of 2.57. What is the acid-dissociation constant, K a, of this a

cid?
Chemistry
1 answer:
lianna [129]2 years ago
6 0

The acid dissociation constant is 1.3 × 10^-3.

<h3>What is acid-dissociation constant?</h3>

The acid-dissociation constant is a constant that shows the extent of dissociation of an acid in solution. We have to set up the reaction equation as shown below;

Let the acid be HA;

                  HA       +      H2O ⇄      H3O^+      +      A^-

since the pH of the solution is 2.57 then;

[H3O^+] = Antilog(-pH) = Antilog(-2.57) = 2.7 × 10^-3

We can see that; [H3O^+]  = [A^-] so;

Ka = (2.7 × 10^-3)^2/(5.5 × 10^–3)

Ka = 1.3 × 10^-3

Learn more about acid-dissociation constant: brainly.com/question/9728159

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Some organic solvents do not work well in liquid-liquid aqueous extractions. Ethanol (HOCH2CH3) is a common inexpensive solvent,
erica [24]

Answer:

See explanation

Explanation:

Extraction has to do with the separation of the components of a mixture by dissolving the mixture in a set up involving two phases. One phase is the aqueous phase (beneath) while the other is the organic phase (on top). The solvents used for the two phases must not be miscible. Water commonly is used for the aqueous phase.

Ethanol is an important solvent in chemistry but the solvent is miscible with water in all proportions. As a result of this, ethanol is a poor solvent for carrying out extraction.

4 0
2 years ago
The coefficients in the balanced chemical equation are used to determine mole ratios.
padilas [110]

Answer:

1 mole of HCl or NaOH gives you 1 mole of H2O , then the number of moles in H2O is: [ 1÷1×1 ] = 1 mole.

Explanation:

6 0
2 years ago
what volume of a 0.155 M calcium hydroxide solution is required to neutralize 28.8 mL of a 0.106 M nitric acid?​
Hitman42 [59]

Answer:

9.85mL

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

Ca(OH)2 + 2HNO3 —> Ca(NO3)2 + 2H2O

From the balanced equation above,

nA (mole of the acid) = 2

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) =?

Mb (Molarity of base) = 0.155 M

Va (volume of the acid) = 28.8 mL

Ma (Molarity of acid) = 0.106 M

Using MaVa/MbVb = nA/nB, the volume of calcium hydroxide (i.e the base) can be obtain as follow:

MaVa/MbVb = nA/nB

0.106 x 28.8 / 0.155 x Vb = 2/1

Cross multiply to express in linear form as shown below:

2 x 0.155 x Vb = 0.106 x 28.8

Divide both side by 2 x 0.155

Vb = (0.106 x 28.8) / (2 x 0.155)

Vb = 9.85mL

Therefore, the Volume of calcium hydroxide is 9.85mL

7 0
3 years ago
Complete and balance the equation for the reaction of sodium with water.<br> Na+_H2O+ H2
valentina_108 [34]

2Na + 2H2O → 2NaOH + H2

The balanced equation

4 0
2 years ago
Denver, Colorado (altitude above sea level is 5,280 ft) has an atmospheric pressure of 633. mm Hg. Calculate the boiling point o
Fed [463]

Answer:

T2 = 94.6 C

Explanation:

Use Clausius-Clayperyon equation.

ln P1/P2 = ∆Hvap/R (1/T2 - 1/T1) where R = 8.314 J/mol-K and T is in degrees K

P1 = 760 mmHg

P2 = 630 mmHg  

T1 = 373 K

T2 = ?

∆Hvap = 40.7 kJ/mole

R = 0.008314 kJ/mole-K (NOTE: change R to units of kJ)

Plug in and solve for T2

ln 760 mmHg/630 mmHg = 40.7 kJ/mole (1/T2 - 1/373K)

T2 = 367.74 K = 94.6 C

8 0
3 years ago
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