6547.9 feet to meters<br> Using dimensional analysis

with the help of balanced chemical equation explain what happens when zinc is put in dilute hydrochloric acid

blagie [28]

They react to form salt ZnCl + hydrogen gas

3 0

2 years ago

What is the voltage in a circuit is the current is 3 amps and the resistance is 3 ohms

ozzi

Answer:

9

Explanation:

V=I*R

3*3

Thats the answer

7 0

2 years ago

You are given a solid that is a mixture of na2so4 and k2so4.

Murljashka [212]

Here we have to calculate the amount of $SO_{4}^{2-}$ ion present in the sample.

In the sample solution 0.122g of $SO_{4}^{2-}$ ion is present.

The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-

K₂SO₄ = 2K⁺ + $SO_{4}^{2-}$

(Na)₂SO₄=2Na⁺ + $SO_{4}^{2-}$

Thus, BaCl₂+ $SO_{4}^{2-}$ = BaSO₄↓ + 2Cl⁻ .

(Na)₂SO₄ and K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of $SO_{4}^{2-}$ ion is precipitated in this reaction.

The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.

Now the molecular weight of BaSO₄ is 233.3 g/mol.

We know the molecular weight of sulfate ion ( $SO_{4}^{2-}$ ) is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of $SO_{4}^{2-}$ ion is present.

Or. we may write in 233.3 g of BaSO₄ 96.06 g of $SO_{4}^{2-}$ ion is present. So in 1 g of BaSO₄ $\frac{96.06}{233.3}=0.411$ g of $SO_{4}^{2-}$ ion is present.

Or, in 0.298 g of the filtered mass (0.298×0.411)=0.122g of $SO_{4}^{2-}$ ion is present.

5 0

3 years ago

If 100 ml of a 0.5 M HCI Solution is diluted with water to 1000ml, what is the new concetration?

Vesna [10]

Answer:

$0.05\ \text{M HCl}$

Explanation:

$V_1$ = Initial volume = 100 mL

$V_2$ = Final volume = 1000 mL

$M_1$ = Initial concentration = 0.5 M

$M_2$ = Final concentration

We have the relation

$\dfrac{M_1}{M_2}=\dfrac{V_2}{V_1}\\\Rightarrow M_2=M_1\dfrac{V_1}{V_2}\\\Rightarrow M_2=0.5\times \dfrac{100}{1000}\\\Rightarrow M_2=0.05\ \text{M HCl}$

The new concentration is $0.05\ \text{M HCl}$ .

3 0

2 years ago

How many sublevels inn the second energy level?

GREYUIT [131]

There are two subshells that are s and p, which are present in the second energy level.

The energy level can be defined as the fixed distances from the nucleus of an atom where electrons may be found. Each energy level is divided into some Subshells. These subshells are known as s-subshell, p-subshell, d-subshell, and f-subshell. This subshell contains some orbitals, these orbitals are the place where there is the maximum probability of getting the electrons. In one orbital, a maximum of two electrons can be present.

Hence, there are two subshells in the second energy level.

Learn more about subshells here:

brainly.com/question/26438203

#SPJ10

4 0

1 year ago

6547.9 feet to meters Using dimensional analysis