Change the 5 - 2t with kcc (keep,change,change)and make it 5+-2t=3t
1) y-intercept => x = 0, => y = f(0) = 0 - 0 + 0 - 36 = -36
2) x-intercept => y = 0 => factor the function (start by dividing by x -2)
f(x) = (x-2)(x-3)(x-6) =0 => x =2, x = 3, x = 6 (these are the x-intercepts)
3) critical points:
between x = 2 and x = 3, there is a local maximum
between x =3 and x = 6 there is a local minimum
3) Shape.
The function comes growing from - infinity.
In the third quadrant the function is negative (it does not pass throuhg the second quadrant)
It enters to the fourth quadrant intercepting the y-axis at y = -36. It continues growing and intercepts the x-axis at x = 2.
It continues increasing until a maximum local positive value, starts to decrease, intercepts the x-axis at x = 3, continues decreasing, becomes negative, gets a local minimum in the fourth quadrant, starts to increase, intercepts the x-axis at x = 6, becomes positive, and continues growing.
Answer:
y = -2x + 3
Step-by-step explanation:
Let's just put the three points together.
(-1, 5) (-4, 11) (-7, 17)
First, let's find the slope with y2 - y1/x2 - x1
Plug in using (-1, 5) and (-4, 11)
11 - 5/-4 + 1 = 6/-3 (simplify)
-2 is the slope
Now plug in (-7, 17) in the equation to get b or the y-intercept)
y = mx + b
17 = -2(-7) + b
17 = 14 + b (subtract 14 on both sides)
3 = b
y = -2x + 3
Answer:
y = 8x - 8
Step-by-step explanation:
y = mx + b is slope-intercept form
m - slope
b - y-intercept
so if you plug in 8 for m and -8 for b you'll get
y = 8(m)x - 8(b)
Hope this helps!!
Step-by-step explanation:
1 .f(x)=
-x+1
f(-1)= (-1)-(-1)+1
f(-1)= 1+1+1
= 3
3.f(x)=-x+1
f( 1)=(1)-1+1
f( 1)=1-1+1
=1
5. f(x)=-x+1
f(3)=
-3+1
= 9-3+1
=7
2. g(x) = 5 - 3x
g( -8)=5-3(-8)
g( -8)=5+24
=29
4.g(x) = 5 - 3x
g(5)=5-3(5)
g(5)=5-15
=-10
6.g(x) = 5 - 3x
g(-3)=5-3(-3)
g(-3)=5+9
=14
