The equation modeling the height of the ball at time,t is given by h=-16t²+48t+6
<span>a. In how many seconds does the ball reach its maximum height?
Time taken for the ball to reach the maximum height will be given by:
h'(t)=-32t+48=0
finding the value of t we get:
32t=48
t=48/32
t=1.5 seconds
Thus the time taken for the ball to reach the maximum time is 1.5 seconds
b]</span><span> What is the ball’s maximum height?
The maximum height will be:
h(1.5)=-16(1.5)</span>²+48(1.5)+6
h(1.5)=42 fee
Answer:
50000y^9.
Step-by-step explanation:
(2y)^4 * (5y)^5
= 2^4 y^4 * 5^5 y^5
= 16y^4 * 3125y^5
= 50000y^9.
Julio scored 30 points and Kris scored 10 points which would give us the total score
