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g100num [7]
3 years ago
14

Patricia is separating 16 soccer cards and 22 baseball cards into groups.Each group will have the same number of cards ,and each

group will have only one kind of sports card.what is the greatest number of cards she can put in each group?how many groups of each type will there be
Mathematics
2 answers:
Art [367]3 years ago
7 0

There would be 2 groups. The greatest amount in each pile is 2 cards.
abruzzese [7]3 years ago
5 0

Answer: There are 8 soccer cards and 11 baseball cards.

Step-by-step explanation:

Since we have given that

Number of soccer cards = 16

Number of baseball = 22

We need to greatest number of cards she can put in each group.

So, H.C.F. of 16 and 22 = 2

Hence, there are 2 cards she can put in each group.

Number of groups of soccer cards is given by

\dfrac{16}{2}=8

Number of groups of baseball cards is given by

\dfrac{22}{2}=11

Hence, there are 8 soccer cards and 11 baseball cards.

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vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ  

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

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- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

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- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

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* Lets solve the problem

- There are two triangles TUW and VWU

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∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

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∵ m∠T = m∠V ⇒ given (right angles)

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∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

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Answer:

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Step-by-step explanation:

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