1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
g100num [7]
3 years ago
14

Patricia is separating 16 soccer cards and 22 baseball cards into groups.Each group will have the same number of cards ,and each

group will have only one kind of sports card.what is the greatest number of cards she can put in each group?how many groups of each type will there be
Mathematics
2 answers:
Art [367]3 years ago
7 0

There would be 2 groups. The greatest amount in each pile is 2 cards.
abruzzese [7]3 years ago
5 0

Answer: There are 8 soccer cards and 11 baseball cards.

Step-by-step explanation:

Since we have given that

Number of soccer cards = 16

Number of baseball = 22

We need to greatest number of cards she can put in each group.

So, H.C.F. of 16 and 22 = 2

Hence, there are 2 cards she can put in each group.

Number of groups of soccer cards is given by

\dfrac{16}{2}=8

Number of groups of baseball cards is given by

\dfrac{22}{2}=11

Hence, there are 8 soccer cards and 11 baseball cards.

You might be interested in
It takes Zoe 12.5 minutes to swim 20 laps around the pool. what is Zoes’s unit rate
Molodets [167]

Answer:

The answer is 1.6

5 0
4 years ago
Read 2 more answers
Which of the following is NOT a solution to the inequality below? 4x+9>63
Sedbober [7]

Answer:

A. 13

Step-by-step explanation:

When you plug the numbers in, 4 times 13 = 52+9=61 and 63 is still greate so anything above 13 would make the sentence correct. So that is why 13 is NOT a solution.

5 0
3 years ago
Read 2 more answers
Find the area of the circle. Round to the nearest tenth. Use 3.14 for π. 14 m circle
Dima020 [189]

Answer:

615.44 m²

Step-by-step explanation:

3.14(14)²= 615.44 m²

6 0
3 years ago
Read 2 more answers
How much would you be willing to rent an additional oven when the order size is 1 dozen cookies
Kamila [148]

The amount that you should be willing to rent an additional oven when the order size is 1 dozen cookies is the amount that is less than the profit of producing those cookies.

<h3 /><h3>What amount should be paid to rent an additional oven?</h3>

The dozen cookies that Kristen’s Cookie Company are about to make are an additional order which means that they do not have the ovens to make it.

They will therefore have to rent an additional oven. If they did this, the amount they pay for the additional oven should not give them losses. They should therefore rent the oven at a cost that is less than the profit they will get for the additional 1 dozen cookies.

Find out more on accepting additional orders at brainly.com/question/25811981.

#SPJ4

3 0
2 years ago
Tutorial
alexandr402 [8]
Happy yu and sorry but alikwnshs
7 0
3 years ago
Other questions:
  • Line passing through the point (4,-7) and has slop of 3
    9·1 answer
  • The weight of an organ in adult males has a​ bell-shaped distribution with a mean of 325 grams and a standard deviation of 25 gr
    9·1 answer
  • Use the method of cylindrical shells to find the volume generated by rotating the region bounded by the given curves about the s
    10·1 answer
  • Find u * v, if u= 12j and v = i + 5j<br> a (1,60)<br> b (0,60)<br> c -60<br> d 60
    7·2 answers
  • Whats bigger 81.9 or 91.91
    10·1 answer
  • The interior angle of a triangle has measures 100°,4y+25 and 3y +20.what is the value of y?
    6·1 answer
  • A firefighter is standing 33 feet away from a 45 foot tall building. The firefighter looks up and sees that a cat that is stuck
    6·1 answer
  • On a number line, graph all the temperature that are warmer than -2 degrees Celsius
    8·1 answer
  • What is the maximum profit Marcia can earn from the<br> picture frames she makes in 1 week?
    5·1 answer
  • I need answer for this math problem​
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!