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vredina [299]
2 years ago
11

A chemist dilutes a 1.0 ml sample of 2.0 m kno3 by adding water to it. if the concentration of the solution that is obtained is

0.0080 m, what is its volume? use m subscript i v subscript i equals m subscript f v subscript f.. 125 ml 250 ml 500 ml 2,000 ml
Chemistry
1 answer:
Nitella [24]2 years ago
8 0

A chemist dilutes a 1.0 ml sample of 2.0M KNO₃ by adding water to it. If the concentration of the solution that is obtained is 0.0080 m, then its volume is 250mL.

<h3>How do we calculate volume?</h3>

Volume for the given equation will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

M₁ = molarity of KNO₃ = 2M

V₁ = volume of KNO₃ = 1mL

M₂ = molarity of final solution = 0.0080M

V₂ = volume of final solution = ?

On putting these values on the above equation, we get

V₂ = (2)(1) / (0.0080) = 250mL

Hence option (2) is correct.

To know more about molarity, visit the below link:

brainly.com/question/24305514

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A 44% wt/wt solution of H2SO4 has a density of 1.343g/ml. What mass of H2SO4 is 60ml of this solution?
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<u>Answer:</u> The mass of sulfuric acid present in 60 mL of solution is 34.1 grams

<u>Explanation:</u>

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44 % (m/m) solution of sulfuric acid. This means that 44 grams of sulfuric acid is present in 100 grams of solution.

To calculate volume of a substance, we use the equation:

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Density of solution = 1.343 g/mL

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Putting values in above equation, we get:

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To calculate the mass of sulfuric acid present in 60 mL of solution, we use unitary method:

In 77.46 mL of solution, mass of sulfuric acid present is 44 g

So, in 60 mL of solution, mass of sulfuric acid present will be = \frac{44g}{77.46mL}\times 60mL=34.1g

Hence, the mass of sulfuric acid present in 60 mL of solution is 34.1 grams

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