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3 years ago

A measure of kinetic energy of particle motion within a substance is_____.

Chemistry

2 answers:

lina2011 [118]3 years ago

6 0

Answer:

temerater

Explanation:

i just did it on odyssey ware

ratelena [41]3 years ago

4 0

Answer: Option (c) is the kinetic energy.

Explanation:

The kinetic energy present within the particles of a substance is known as thermal energy. Measure of average kinetic energy of particles of a substance is known as temperature.

Whereas heat defined as the transfer of thermal energy from a hot object to a cold object.

Enthalpy is defined as the heat gained or lost by a substance in a chemical reaction.

Thermodynamics is the study of relation between heat and work with chemical or physical changes.

Thus, we can conclude that a measure of kinetic energy of particle motion within a substance is temperature.

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2. Write balanced chemical reactions for the following: (1 point each, 4 points total) a. Cobolt-60 undergoes beta decay b. Amer

kondaur [170]

A nuclear reaction must lead to changes in the nucleus of an atom.

<h3>What is a nuclear reaction?</h3>

The term nuclear reaction refers to a reaction in which a new nucleus is formed. The following are the nuclear reactions;

a) 60/27Co -----> 60/28 Ni + 0/-1 e

b) 241/95 Am ------> 237/93Np + 4/2He

c) 60/29 ----> 60/28 Ni + 0/1 e

d) 66/31 Ga + 0/-1 e -----> 66/30 Zn

Learn more about nuclear reactions:brainly.com/question/16526663

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5 0

2 years ago

A thermometer having first-order dynamics with a time constant of 1 min is placed in a temperature bath at 100oF. After the ther

sveticcg [70]

Answer:

(a) See below

(b) 103.935 °F; 102.235 °F

Explanation:

The equation relating the temperature to time is

$T = T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )$

1. Calculate the thermometer readings after 0.5 min and 1 min

(a) After 0.5 min

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-0.5/1} \right )\\ & = & 100 + 10\left (1 - e^{-0.5} \right )\\ & = & 100 + 10 (1 - 0.6065)\\ & = & 100 + 10(0.3935)\\ & = & 100 + 3.935\\ & = & 103.935\,^{\circ}F\\\end{array}$

(b) After 1 min

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-1/1} \right )\\ & = & 100 + 10\left (1 - e^{-1} \right )\\ & = & 100 + 10 (1 - 0.3679)\\ & = & 100 + 10(0.6321)\\ & = & 100 + 6.321\\ & = & 106.321\,^{\circ}F\\\end{array}$

2. Calculate the thermometer reading after 2.0 min

T₀ =106.321 °F

ΔT = 100 - 106.321 °F = -6.321 °F

t = t - 1, because the cooling starts 1 min late

$\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-(t - 1)/\tau} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-(2 - 1)/1} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-1} \right )\\ & = & 106.321 - 6.321 (1 - 0.3679)\\ & = & 106.321 - 6.321 (0.6321)\\ & = & 106.321 - 3.996\\ & = & 102.325\,^{\circ}F\\\end{array}$

3. Plot the temperature readings as a function of time.

The graphs are shown below.

6 0

3 years ago

An object with a mass of 3.2kg has a force of 16.3 newtons to the right and 6.7 newtons to the left applied to it. What is the r

Pepsi [2]

Answer:

3m/s²

Explanation:

Given parameters:

Mass of object = 3.2kg

Force to the right = 16.3N

Force to the left = 6.7N

Unknown:

Acceleration of the object = ?

Solution:

To solve this problem, we use newtons second law of motion;

Net force = mass x acceleration

Net force on object = Force to the right - Force to the left

Net force = 16.3N - 6.7N = 9.6N

So;

9.6 = 3.2 x a

a = $\frac{9.6}{3.2}$ = 3m/s²

7 0

2 years ago

A grade 8 students burnt white phosphorus in the air contained in a bell jar. what will be the volume of the renaming air in the

jok3333 [9.3K]

Try d cuz if im not mistaken if you burnt white phosphorus all the gas is going to take most the air

5 0

2 years ago

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In 1990, the northern spotted owl was listed as endangered. Because of this, millions of acres of forests in the Pacific

Gwar [14]

Answer:

the endangered spices act

Explanation: The US Endangered Species Act (ESA) is our nation's most effective law to protect at-risk species from extinction, with a stellar success rate: 99% of species listed on it have avoided extinction.

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3 years ago